Chapter 6: Problem 20
Exer. 5-40: Find the amplitude, the period, and the phase shift and sketch the graph of the equation. $$ y=\sin \left(\frac{1}{2} x+\frac{\pi}{4}\right) $$
Short Answer
Expert verified
Amplitude: 1, Period: \(4\pi\), Phase shift: \(-\frac{\pi}{2}\).
Step by step solution
01
Identify the Standard Form
Identify that the given equation, \( y = \sin\left(\frac{1}{2}x + \frac{\pi}{4}\right) \), is of the form \( y = \sin(bx + c) \).
02
Find the Amplitude
For the sine function, the amplitude is the coefficient of the sine term. Here, the sine function is \( \sin\left(\frac{1}{2}x + \frac{\pi}{4}\right) \), and the coefficient is 1. Therefore, the amplitude is 1.
03
Calculate the Period
The period of the sine function is calculated using the formula \( \frac{2\pi}{|b|} \). In this case, \( b = \frac{1}{2} \), so the period is \( \frac{2\pi}{\frac{1}{2}} = 4\pi \).
04
Determine the Phase Shift
To find the phase shift, use the formula \( -\frac{c}{b} \). Here, \( c = \frac{\pi}{4} \) and \( b = \frac{1}{2} \). The phase shift is \(-\frac{\frac{\pi}{4}}{\frac{1}{2}} = -\frac{\pi}{2}\), indicating a shift to the left by \( \frac{\pi}{2} \).
05
Sketch the Graph
To sketch the graph, begin at the phase shift point of \(-\frac{\pi}{2}\) on the x-axis. Recognize that the sine wave will complete one full cycle every \(4\pi\) units. Since the amplitude is 1, the graph oscillates between -1 and 1. Plot these characteristics, ensuring the wave repeats its pattern.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Amplitude
In trigonometric functions, the amplitude is a crucial concept to grasp, especially when dealing with sinusoidal functions like sine and cosine. Amplitude refers to the height of the wave-curve from the centerline to the peak. It's the maximum displacement from the wave's central axis. For the function \( y = \sin\left(\frac{1}{2}x + \frac{\pi}{4}\right) \), the amplitude is found by looking at the coefficient of the sine function, which is 1 in this case. Therefore, the amplitude is 1. This means the graph of the function will have peaks reaching 1 above the centerline and troughs dipping 1 below.
- Amplitude gives the wave its height.
- In the context of sine and cosine functions, it denotes half the distance the graph travels from top to bottom.
Calculating the Period
The period of a trigonometric function is the distance it takes for the function to complete one full cycle. For sine and cosine functions, this is calculated using the formula \( \frac{2\pi}{|b|} \), where \( b \) is the coefficient of \( x \). In our function, \( y = \sin\left(\frac{1}{2}x + \frac{\pi}{4}\right) \), \( b \) is \( \frac{1}{2} \). Plugging this into the formula gives us a period of \( \frac{2\pi}{\frac{1}{2}} = 4\pi \). This calculation tells us that the function repeats its pattern every \( 4\pi \) units along the x-axis.
- Period measures how long it takes to complete a cycle.
- It's inversely related to the frequency of the wave: the smaller the \( b \), the longer the period.
Determining the Phase Shift
Phase shift in trigonometric functions is a horizontal shift along the x-axis. This shift occurs because of the constant added to the \( x \) term inside the sinusoidal function. In our function, \( y = \sin\left(\frac{1}{2}x + \frac{\pi}{4}\right) \), the phase shift is calculated using \( -\frac{c}{b} \), where \( c = \frac{\pi}{4} \) and \( b = \frac{1}{2} \). Solving \( -\frac{\frac{\pi}{4}}{\frac{1}{2}} \) leads to a phase shift of \( -\frac{\pi}{2} \), which means the wave is shifted to the left by \( \frac{\pi}{2} \).
- Phase shift affects where the wave starts on the graph.
- It can move the graph left or right, depending on the sign of the shift.