Chapter 6: Problem 46
Exer. 39-46: Refer to the graph of \(y=\sin x\) or \(y=\cos x\) to find the exact values of \(x\) in the interval \([0,4 \pi]\) that satisfy the equation. $$ \cos x=-\frac{1}{2} $$
Short Answer
Expert verified
The exact values of \( x \) are \( \frac{2\pi}{3}, \frac{4\pi}{3}, \frac{8\pi}{3}, \frac{10\pi}{3} \).
Step by step solution
01
Understand the Equation
The given equation is \( \cos x = -\frac{1}{2} \). We need to find the values of \( x \) in the interval \([0, 4\pi]\) that satisfy this condition.
02
Identify the General Solutions
Consider the unit circle where \( \cos \theta = -\frac{1}{2} \). This occurs at an angle of \( \theta = \frac{2\pi}{3} \) and \( \theta = \frac{4\pi}{3} \) since these are the angles on the unit circle within \([0,2\pi]\) where cosine equals \(-\frac{1}{2}\).
03
Extend the Solutions to the Interval
Since trigonometric functions are periodic, extend the solutions to the interval \([0, 4\pi]\), which includes two cycles of \(2\pi\). The solutions are \( x = \frac{2\pi}{3} + 2\pi k \) and \( x = \frac{4\pi}{3} + 2\pi k \), where \( k \) is an integer.
04
Calculate Specific Values in the Interval
Calculate the specific values for \( k = 0, 1, 2 \) to find which values lie within \([0, 4\pi]\):- For \( k = 0 \): \( x = \frac{2\pi}{3}, \frac{4\pi}{3} \)- For \( k = 1 \): \( x = \frac{2\pi}{3} + 2\pi = \frac{8\pi}{3}, \frac{4\pi}{3} + 2\pi = \frac{10\pi}{3} \)- For \( k = 2 \): \( x = \frac{2\pi}{3} + 4\pi \) exceeds \( 4\pi \), similarly \( x = \frac{4\pi}{3} + 4\pi \) exceeds \( 4\pi \).
05
Compile the Exact Values
Considering above calculations, the exact values of \( x \) within \([0, 4\pi]\) that satisfy \( \cos x = -\frac{1}{2} \) are \( \frac{2\pi}{3}, \frac{4\pi}{3}, \frac{8\pi}{3}, \frac{10\pi}{3} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Unit Circle
The unit circle is a fundamental concept in trigonometry, used to define the sine and cosine of an angle. It is a circle with a radius of 1, centered at the origin (0, 0) of a coordinate plane. This circle is particularly useful when analyzing trigonometric functions because the x-coordinate of any point on the circle corresponds to the cosine of an angle, while the y-coordinate corresponds to the sine. This makes it simple to visualize and determine values for angles.
- Each point on the unit circle represents a complex number associated with an angle measured from the positive x-axis.
- Angles can be measured in radians, where one full revolution around the circle is equal to \(2\pi\) radians.
- The unit circle helps find exact values of trigonometric functions without needing a calculator.
Cosine Function
The cosine function is an important trigonometric function that shows the relation between the angle and length of the adjacent side in a right triangle. In the context of the unit circle, the cosine of an angle is the x-coordinate of the point where the terminal side of the angle intersects the circle.
- The cosine function is denoted as \(\cos(x)\) and maps real numbers (angles in radians) to real values ranging between -1 and 1.
- The graph of the cosine function is a wave that starts at 1 when \(x=0\) and periodically repeats every \(2\pi\).
- The function decreases to 0 at \(\pi/2\), to -1 at \(\pi\), back to 0 at \(3\pi/2\), and returns to 1 at \(2\pi\).
Periodic Functions
Periodic functions are functions that repeat their values at regular intervals. In trigonometry, sine and cosine functions are classic examples of periodic functions with a fundamental period of \(2\pi\), meaning they repeat themselves every \(2\pi\) radians.
- The main property of periodic functions is their ability to continue infinitely with repetition—this makes them incredibly useful in modeling cyclical phenomena.
- The cosine function repeats every \(2\pi\), which allows us to extend solutions beyond the initial cycle.
- For the equation \(\cos x = -\frac{1}{2}\), we find the initial solutions within one cycle \([0, 2\pi]\) and duplicate these with an offset of \(2\pi\).