Chapter 5: Problem 40
Exer. 37-42: Sketch the graph of \(f\). $$ f(x)=\ln |x-1| $$
Short Answer
Expert verified
The graph of \(f(x) = \ln |x-1|\) has two branches with a vertical asymptote at \(x = 1\), both approaching \(-\infty\) as they near \(x = 1\), and rising to \(\infty\) as \(|x|\) increases.
Step by step solution
01
Understanding the Function
The function given is \(f(x) = \ln |x-1|\), where \(\ln\) indicates the natural logarithm and \(|x-1|\) ensures we take the logarithm of a positive value since logarithm is only defined for positive values.
02
Determining the Domain
The function \(|x-1|\) is positive and non-zero if \(x eq 1\). Thus, the domain of \(f(x) = \ln |x-1|\) is \(x \in (-\infty, 1) \cup (1, \infty)\). The function is not defined for \(x = 1\) because \(|x-1| = 0\) at \(x = 1\).
03
Understanding the Behavior Near the Domain Boundaries
As \(x\) approaches 1 from the left (\(x \to 1^-\)), \(x - 1 \to 0^-\), thus \(f(x) = \ln |x-1|\to -\infty\). As \(x\) approaches 1 from the right (\(x \to 1^+\)), \(x - 1 \to 0^+\), so \(f(x) = \ln |x-1| \to -\infty\).
04
Behavior as \(x\) Goes to Infinity or Negative Infinity
As \(x\) approaches infinity (\(x \to \infty\)), \(x - 1 \to \infty\), and \(f(x) = \ln |x-1| \to \infty\). Similarly, as \(x\) approaches negative infinity (\(x \to -\infty\)), \(x - 1 \to -\infty\) and \(f(x) = \ln |x-1| \to \infty\).
05
Graphing the Function
The graph consists of two branches. For \(x < 1\), the plot approaches negative infinity as it nears \(x = 1\), and climbs up to positive infinity as \(x\) decreases further. For \(x > 1\), the situation is similar: the plot approaches negative infinity as it nears \(x = 1\), and climbs up to positive infinity as \(x\) increases further. Together, this creates a graph with a vertical asymptote at \(x = 1\), and each branch increases without bound away from the asymptote.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Functions
Graphing a function involves understanding how the output, or y-value, changes as the input, or x-value, moves across the number line. Essentially, it’s a visual snapshot of all the ordered pairs \((x, f(x))\) that satisfy the function. For \(f(x) = \ln |x-1|\), this process requires special attention to the properties of logarithms and absolute values.
- The function \(\ln\) stands for the natural logarithm, defined only for positive numbers.
- The absolute value, \(|x-1|\), ensures that \(\ln\) only ever receives positive inputs.
Vertical Asymptote
A vertical asymptote is a place where a graph of a function approaches a specific x-value but never touches or crosses it. For our function, \(f(x) = \ln |x-1|\), we find a vertical asymptote at \(x = 1\). This occurs because as \(x\) gets closer to 1, the expression \(x-1\) gets closer to zero, causing \(\ln |x-1|\) to plummet towards negative infinity.
For function behaviors involving asymptotes:
For function behaviors involving asymptotes:
- As \(x\) nears 1 from either the left or the right, \(f(x)\) decreases without bound.
- The function never achieves or crosses the x-coordinate of the asymptote.
Domain of a Function
The domain of a function represents all possible input values (x-values) for which the function is defined. For \(f(x) = \ln |x-1|\), this means considering the condition that the argument of the logarithm must be positive and non-zero. The absolute value, \(|x-1|\), must be positive, implying that x cannot equal 1.
Thus, the domain becomes all real numbers except 1, expressed in interval notation as \((-\infty, 1) \cup (1, \infty)\). This format specifies:
Thus, the domain becomes all real numbers except 1, expressed in interval notation as \((-\infty, 1) \cup (1, \infty)\). This format specifies:
- For x-values to the left of 1, including extremely negative numbers, the function can compute outputs successfully.
- For x-values directly at 1, the function is not defined, thus producing a gap or break in the domain.
- For x-values to the right of 1, even into positive infinity, the function remains defined and operational.