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Chapter 9: Problem 126

The sum of the numbers in the \(n\) th row of Pascal's Triangle is \(2^{n}\).

Short Answer

Expert verified
The sum of the numbers in the \(n\) th row of Pascal's Triangle is \(2^{n}\), which is proven by formulating the sum of each row in terms of the binomial coefficients and showcasing the equivalence when \(a = 1\) and \(b = 1\) in the binomial expansion.

Step by step solution

01

Understanding Pascal's Triangle

Pascal's triangle is a triangular array of the binomial coefficients. Each number in a row of the triangle is the sum of the two numbers directly above it. In this triangular arrangement, the \(n\) th row corresponds to the coefficients of \((a + b)^{n}\) in the binomial expansion. So, a row in Pascal's triangle is also the coefficients of the expansion of a binomial equation raised to the power \(n\).
02

Formulating terms in Pascal's Triangle

The \(n\) th row of Pascal's triangle will have \((n+1)\) terms and these coefficients correspond to the terms \({n \choose 0}, {n \choose 1}, ..., {n \choose n}\) in the binomial expansion of \((a + b)^{n}\). These are also known as binomial coefficients.
03

Proving the Sum of the \(n\) th row

The sum of the elements in the \(n\) th row can be written as \({n \choose 0} + {n \choose 1} + ... + {n \choose n}\). This same result can also be obtained by substituting \(a = 1\) and \(b = 1\) in the expansion of \((a + b)^{n}\), which yields \(2^{n}\). This is because substituting 1 for \(a\) and \(b\) in the expansion of \((a + b)^{n}\) and simplifying gives \(2^{n}\). This proves the sum of the numbers in the \(n\) th row of Pascal's Triangle is \(2^{n}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficients
Binomial coefficients are the numbers that appear as the entries of Pascal's Triangle. They represent the different ways you can choose a number of items from a larger set. For example, in combinations, how many ways you can choose 2 objects from 5, is represented by a binomial coefficient.
  • Binomial coefficients are denoted as \(\binom{n}{k}\), where \(n\) is the total number of items, and \(k\) is the number of items to choose.
  • In Pascal's Triangle, each number is derived from the sum of the two numbers directly above it. This means that each row of the triangle builds on the one directly preceding it.
These coefficients are integral to understanding the structure behind binomial expansions, as they dictate the terms in formulas like \((a+b)^n\). Hence, learning about binomial coefficients is a fundamental step in delving into more complex mathematical concepts.
Binomial Theorem
The Binomial Theorem provides a way to expand expressions that are raised to a power. It states that \[(a+b)^n = \binom{n}{0}a^nb^0 + \binom{n}{1}a^{n-1}b^1 + ... + \binom{n}{n}a^0b^n\].
  • The expansion reflects the distribution of the coefficients we find in Pascal's Triangle.
  • The theorem is a powerful algebraic tool that lets us solve complex problems by breaking them into simpler ones.
In more straightforward terms, for any given power \(n\), the expression \((a + b)^n\) can be broken down into a sum of terms constructed using binomial coefficients. Each term includes the coefficients multiplied by powers of \(a\) and \(b\). Understanding this concept is crucial because it allows you to apply the Binomial Theorem to algebraic expressions, thereby simplifying the process of expansion.
Combinatorics
Combinatorics is an area of mathematics that focuses on counting, arrangement, and combination of objects. It's the broader science where binomial coefficients and the Binomial Theorem are applied.
  • It involves counting techniques, such as permutations and combinations, to determine how objects can be arranged or grouped.
  • The applications of combinatorics are vast and include areas like probability, geometry, and computer science.
Understanding combinatorics is essential for grasping the core logic behind many mathematical concepts, including those seen in calculus and algebra. Since the field focuses on counting and arrangement issues, the clear understanding of Pascal's Triangle and its connection to these methods is crucial. Overall, combinatorics aids in solving various real-world problems where logical arrangement and selection are key.

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Most popular questions from this chapter

Find the indicated term of the sequence. $$\begin{aligned} &a_{n}=(-1)^{n}(3 n-2)\\\ &a_{25}= \end{aligned}$$

Find the binomial coefficient. \(\left(\begin{array}{l}20 \\ 20\end{array}\right)\)

Write the first five terms of the sequence defined recursively. Use the pattern to write the \(n\) th term of the sequence as a function of \(n .\) (Assume \(n\) begins with 1.) $$a_{1}=6, a_{k+1}=a_{k}+2$$

Use the Binomial Theorem to expand and simplify the expression. \((2 y-5)^{3}\)

Write the first five terms of the sequence (a) using the table feature of a graphing utility and (b) algebraically. (Assume \(n\) begins with 0.) $$a_{n}=\frac{n^{2}}{(n+1) !}$$
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