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Use the Binomial Theorem to expand and simplify the expression. \((2 y-5)^{3}\)

Short Answer

Expert verified
The expanded and simplified form of \((2 y-5)^3\) is \(8y^3 - 60y^2 + 150y - 125\).

Step by step solution

01

Write down the forms for each term

We start the problem by writing the general form for each term in the binomial expansion. The general form for each term in the expansion of \((a+b)^n\) is \(\binom{n}{r} a^{n-r} b^{r}\), where \(r\) starts from 0 to \(n\). So, for \((2y-5)^3\), we will have four terms, with respective forms \(\binom{3}{0} (2y)^{3-0} (-5)^0\), \(\binom{3}{1} (2y)^{3-1} (-5)^1\), \(\binom{3}{2} (2y)^{3-2} (-5)^2\), \(\binom{3}{3} (2y)^{3-3} (-5)^3\).
02

Substitute values and calculate

Now, we substitute and calculate each term. \(\binom{3}{0} (2y)^{3-0} (-5)^0\) equals \(1*(8y^3)*1 = 8y^3\), \(\binom{3}{1} (2y)^{3-1} (-5)^1\) equals \(-3*(4y^2)*5 = -60y^2\), \(\binom{3}{2} (2y)^{3-2} (-5)^2\) equals \(3*(2y)*25 = 150y\), and \(\binom{3}{3} (2y)^{3-3} (-5)^3\) equals \(-125\).
03

Sum all the terms

Finally, we sum all the terms calculated in step 2: \(8y^3 - 60y^2 + 150y - 125\). This is the expanded form of \((2 y-5)^3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Expansion
Binomial expansion is a powerful algebraic technique that allows us to expand expressions of the form \((a+b)^n\). This method uses the Binomial Theorem, which gives a formula to express any nth power of a binomial as a sum of terms. The formula is defined as:
  • \( \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r \)
Each term in the sum involves a binomial coefficient \( \binom{n}{r} \), which is often pronounced "n choose r". It represents the number of ways to choose r elements from a set of n elements. By using this formula, especially for small values of n, we can efficiently expand binomials into polynomial expressions. Here's how:
  • Determine the terms of the binomial \( (a+b) \).
  • Identify the exponent n of the binomial.
  • Substitute the values into the binomial formula for each term, varying r from 0 to n.
  • Compute and sum each term to get the expanded form.
Practicing this method will improve your speed and accuracy with algebraic manipulations, making polynomial handling much easier.
Combinatorics
Combinatorics, a fundamental branch of mathematics, deals with counting, arrangement, and combination strategies. It plays a critical role in the binomial expansion through the binomial coefficients. These coefficients are a practical application of combinatorics, symbolized as \( \binom{n}{r} \), providing the number of ways to choose r items from a total of n items without regard to order.
When we expand binomials using the Binomial Theorem, each term's coefficient is determined by a binomial coefficient. For example, when expanding \((2y-5)^3\), we have coefficients like \( \binom{3}{0}, \binom{3}{1}, \binom{3}{2}, \binom{3}{3} \), which are 1, 3, 3, and 1 respectively.
These coefficients are readily found in Pascal's Triangle, a geometric arrangement of numbers where each number is the sum of the two directly above it in the triangle. Understanding the connection between binomial coefficients and combinations helps students deepen their grasp on counting methodologies and prepares them for more advanced probability and statistics topics.
Polynomial Expansion
Polynomial expansion refers to the process of expanding expressions that involve powers of sums into simpler polynomials. A polynomial is an expression involving multiple terms, usually with different powers of a variable. The binomial expansion is a specific type of polynomial expansion.
When using binomial expansion as a method of polynomial expansion, you transform an expression like \((a+b)^n\) into a polynomial with n+1 terms. The powers in the polynomial decrease from n to 0 for the term \(a\), while they increase from 0 to n for the term \(b\).
For instance, after applying the binomial theorem to \((2y-5)^3\), we arrive at the polynomial: \(8y^3 - 60y^2 + 150y - 125\). Each term in this polynomial corresponds to a distinct combination of the terms \((2y)\) and \((-5)\), each multiplied by a different binomial coefficient.
  • The highest power of \(y\) corresponds to the first term, \(8y^3\).
  • The powers decrease, reflected in the sequence: \(8y^3, -60y^2, 150y\).
  • The last term, \(-125\), has no y component because it's \((-5)^3\).
By breaking down binomial expressions into polynomials, we better understand the structure of algebraic expressions, making calculations and simplifications more user-friendly.

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