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Use a sketch to find the exact value of \(\tan \left(\sin ^{-1} \frac{5}{13}\right)\) (Section \(5.7,\) Example 7 )

Short Answer

Expert verified
The exact value of \( \tan (\sin^{-1} (\frac{5}{13}) \) is \(\frac{5}{12}\).

Step by step solution

01

Sketch and label a right triangle

Construct a right triangle using the given information. Since \(\sin^{-1}(\frac{5}{13})\) means the angle whose sine is \(\frac{5}{13}\), we can denote the side opposite the angle as 5 (since sine is the ratio of the opposite side to the hypotenuse in a right triangle) and the hypotenuse as 13.
02

Determine the adjascent side

Use the Pythagorean theorem to determine the length of the other side. The theorem states that in any right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides. Hence, \(a=\sqrt{13^2-5^2}=12\).
03

Compute the value of \(\tan\)

Finally, \(\tan\) of an angle in a right triangle is defined as the ratio of the length of the side opposite the angle to the side adjacent to the angle. Hence, \(\tan(\sin^{-1}(\frac{5}{13}))= \frac{5}{12}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Right Triangle
A right triangle is a type of triangle that has one angle measuring exactly 90 degrees. This is known as the right angle. Right triangles are special because they allow us to apply various trigonometric functions in practical scenarios. These functions are crucial for finding distances, slopes, and orientation in fields as diverse as architecture, engineering, and astronomy.
  • In a right triangle, the longest side, opposite to the right angle, is called the hypotenuse.
  • The other two sides are referred to as the legs, generally termed as opposite and adjacent regarding a specific non-right angle.
  • Right triangles are foundational in trigonometry, which studies the mathematical relationships that exist among the angles and sides of triangles.
When dealing with right triangles, visualization through sketches can simplify understanding. Recognizing which side is opposite the angle and which is adjacent can aid in applying trigonometric identities correctly.
Overall, right triangles provide a simple yet powerful framework to explore trigonometric relationships.
Pythagorean Theorem
The Pythagorean theorem is perhaps one of the most well-known principles in mathematics. It specifically applies to right triangles and establishes a relationship between the lengths of the sides. The theorem is stated as: \[c^2 = a^2 + b^2\] where \(c\) represents the hypotenuse, and \(a\) and \(b\) are the legs of the triangle.
  • This theorem helps to find the missing side of a right triangle if the lengths of the other two are known.
  • It is essential in the derivation and usage of trigonometric functions, including sine, cosine, and tangent.
  • Beyond geometry, it also plays a role in algebra and calculus, providing foundational concepts for higher mathematics.
In the context of the exercise, using the Pythagorean theorem allowed us to calculate the adjacent side of the triangle once we knew the hypotenuse and the opposite side. Understanding the theorem aids in translating real-world dimensions into calculable equations, reflecting its extensive utility.
Sine
The sine function is a fundamental trigonometric concept that denotes the ratio of two specific sides in a right triangle. It is expressed as:
\[ ext{sine}( heta) = rac{ ext{opposite side}}{ ext{hypotenuse}}\]
This indicates how the sine value changes as the angle \(\theta\) in a triangle changes.
  • The sine function is useful in representing periodic phenomena, like waves, sound, and light.
  • It helps to calculate angles and distances, integral in navigation, physics, and engineering.
  • Inverse sine, or \(\sin^{-1}\), often helps to find angle measures from known side ratios, as seen in this exercise.
For instance, when given \(\sin^{-1}(\frac{5}{13})\), we're finding the angle whose sine is \(\frac{5}{13}\). Such inverse functions are valuable for problem-solving, allowing you to reverse the standard computation of the sine function to find angles instead.
Tangent
Tangent is another crucial trigonometric function that expresses the ratio of the opposite side to the adjacent side in a right triangle:\[ ext{tangent}( heta) = rac{ ext{opposite side}}{ ext{adjacent side}}\]Tangent values vary as the angle \(\theta\) changes in a triangle.
  • The tangent function is helpful when predicting how a slope or angle might affect other measurements and configurations.
  • It is widely used in physics to understand inclines, projectile motion, and other applications involving angles.
  • In the exercise, calculating the tangent from a given angle is crucial to solving trigonometric problems.
Understanding tangent is fundamental when exploring the relationships between different trigonometric functions. In the given exercise, knowing that \(\tan(\sin^{-1}(\frac{5}{13}))\) gives the ratio of 5 (opposite side) over 12 (adjacent side) demonstrates the interconnection between various trigonometric concepts.

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Most popular questions from this chapter

The table shows the price of a gallon of unleaded premium gasoline. For each price, the table lists the number of gallons per day that a gas station sells and the number of gallons per day that can be supplied. $$\begin{array}{lll}{\text { Price per }} & {\text { Gallons Demanded }} & {\text { Gallons Supplied }} \\ {\text { Gallon }} & {\text { per Day }} & {\text { per Day }} \\ {\$ 3.20} & {1400} & {200} \\ {\$ 3.60} & {1200} & {600} \\ {\$ 4.40} & {800} & {1400} \\ {\$ 4.80} & {600} & {1800}\end{array}$$ The data in the table are described by the following demand and supply models: Demand Model \(\quad\) Supply Model \(p=-0.002 x+6 \quad p=0.001 x+3\) a. Solve the system and find the equilibrium quantity and the equilibrium price for a gallon of unleaded premium gasoline. b. Use your answer from part (a) to complete this statement: If unleaded premium gasoline is sold for _____ per gallon, there will be a demand for ______ gallons per day and ______ gallons will be supplied per day.

Determine the amplitude, period, and phase shift of \(y=-2 \cos \left(2 x-\frac{\pi}{2}\right) .\) Then graph one period of the function. (Section 5.5, Example 6)

A television manufacturer makes rear-projection and plasma televisions. The profit per unit is 125 for the rear-projection televisions and 200 for the plasma televisions. a. Let \(x=\) the number of rear-projection televisions manufactured in a month and let \(y=\) the number of plasma televisions manufactured in a month. Write the objective function that models the total monthly profit. b. The manufacturer is bound by the following constraints: \(\cdot\) Equipment in the factory allows for making at most 450 rear-projection televisions in one month. \(\cdot\) Equipment in the factory allows for making at most 200 plasma televisions in one month. \(\cdot\) The cost to the manufacturer per unit is 600 for the rear-projection televisions and 900 for the plasma televisions. Total monthly costs cannot exceed 360,000. Write a system of three inequalities that models these constraints. c. Graph the system of inequalities in part (b). Use only the first quadrant and its boundary, because \(x\) and \(y\) must both be nonnegative. d. Evaluate the objective function for total monthly profit at each of the five vertices of the graphed region. [The vertices should occur at \((0,0),(0,200),(300,200)\) \((450,100), \text { and }(450,0) .]\) e. Complete the missing portions of this statement: The television manufacturer will make the greatest profit by manufacturing _____ rear- projection televisions each month and _____ \(-\) plasma televisions each month. The maximum monthly profit is $_____.

Sketch the graph of the solution set for the following system Of inequalities: $$ \left\\{\begin{array}{l} {y \geq n x+b(n<0, b>0)} \\ {y \leq m x+b(m>0, b>0)} \end{array}\right. $$

Solve the system for \(x\) and \(y\) in terms of \(a_{1}, b_{1}, c_{1}, a_{2}, b_{2},\) and \(c_{2}\) $$\left\\{\begin{array}{l} {a_{1} x+b_{1} y=c_{1}} \\ {a_{2} x+b_{2} y=c_{2}} \end{array}\right.$$

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