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Graph the solution set of each system of inequalities or indicate that the system has no solution. $$ \left\\{\begin{array}{l} {3 x+y \leq 6} \\ {x>-2} \\ {y \leq 4} \end{array}\right. $$

Short Answer

Expert verified
The solution set for the system of inequalities is the overlapping region on the graph of all the individual inequalities.

Step by step solution

01

Graph the Inequality 1

Start with the first inequality \(3x + y \leq 6\). This inequality can be rewritten as \(y \leq -3x + 6\). Plot the line \(y = -3x + 6\). Because our inequality sign is '\(\leq\)', the solution of this inequality will include the line and the area beneath it.
02

Graph the Inequality 2

Now, plot the second inequality \(x > -2\). This is a vertical line at \(x = -2\). As the inequality is 'greater than', our solution lies to the right side of the line.
03

Graph the Inequality 3

Next, graph the third inequality \(y \leq 4\). This is a horizontal line at \(y = 4\). As the inequality is 'less than or equal to', our solution will be the line and the area beneath it.
04

Find the Intersection Region

The solution to the system of inequalities is the region where the solutions to all three inequalities overlap. Identify this region on your graph.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

System of Inequalities
When we talk about a system of inequalities, we are referring to multiple inequalities that are considered together. Much like a system of equations, these groups of inequalities have a set of solutions that satisfy all inequalities in the system simultaneously.

The key point is that each inequality can be visualized as a region in a coordinate plane, and when dealing with a system, we are looking for the overlap of these regions. Here, each individual inequality divides the plane into two halves: one that satisfies the inequality and one that does not. The solutions of the system are then found in the areas where these halves intersect.

For instance, a simple system might consist of inequalities like those in the provided exercise – each one contributes to the narrowing down of the feasible solution space. Solving these systems can be especially helpful in real-world applications such as determining constraints for budgeting issues or in designing objects within certain dimensional limits.
Inequality Graphing
Inequality graphing is a visual representation that illustrates the solutions to inequalities on a coordinate plane. Each graphed inequality typically results in a shaded region, which demonstrates all the possible solutions.

To properly graph an inequality, one must first manipulate it into a recognizable form, often resembling the equation of a line. Then, the boundary of the inequality (the line itself) is drawn. If the inequality is strict (< or >), the line is dashed indicating that points on the line are not included as solutions. If it's inclusive (≤ or ≥), the line is solid, including all points on it.

The final and crucial step involves shading: the region of the graph that satisfies the inequality is shaded, which visually captures all the possible solutions. This process is repeated for each inequality in the system, and where the shaded regions overlap is the solution set to the system. In the context of the textbook exercise, graphing each inequality carefully and finding their intersection helps identify the feasible region that satisfies the entire system.
Linear Inequalities
Linear inequalities are similar to linear equations but with inequality signs instead of an equal sign. They describe a range of possible values for variables that make the inequality true. These inequalities can be one-dimensional or two-dimensional, and they can involve one variable (e.g., x < 4) or two (e.g., 2x + 3y > 6).

Graphically, linear inequalities in two variables form half-planes in the coordinate system. The edge of the half-plane, where the inequality changes from true to false, is a straight line, either dashed or solid. The key aspects when graphing include identifying which side of the boundary line to shade and whether to use a dashed or solid line, as mentioned previously.

Once each inequality is graphed, solving the system is all about finding where all these half-planes intersect, which represents all the solutions that satisfy every inequality in the system. The exercise provided helps practice these concepts by requiring a graph that combines several linear inequalities into a comprehensive visual representation of their collective solution set.

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Most popular questions from this chapter

Use the exponential growth model, \(A=A_{0} e^{k t},\) to solve this exercise. In \(1975,\) the population of Europe was 679 million. By \(2015,\) the population had grown to 746 million. a. Find an exponential growth function that models the data for 1975 through 2015 b. By which year, to the nearest year, will the European population reach 800 million? (Section \(4.5,\) Example 1 )

Determine whether each statement makes sense or does not make sense, and explain your reasoning. When graphing \(3 x-4 y<12\), it's not necessary for me to graph the linear equation \(3 x-4 y=12\) because the inequality contains a \(<\) symbol, in which equality is not included.

Harsh, mandatory minimum sentences for drug offenses account for more than half the population in U.S. federal prisons. The bar graph shows the number of inmates in federal prisons, in thousands, for drug offenses and all other crimes in 1998 and 2010. (Other crimes include murder, robbery, fraud, burglary, weapons offenses, immigration offenses, racketeering, and perjury.) a. In 1998, there were 60 thousand inmates in federal prisons for drug offenses. For the period shown by the graph, this number increased by approximately 2.8 thousand inmates per year. Write a function that models the number of inmates, y, in thousands, for drug offenses x years after 1998. b. In 1998, there were 44 thousand inmates in federal prisons for all crimes other than drug offenses. For the period shown by the graph, this number increased by approximately 3.8 thousand inmates per year. Write a function that models the number of inmates, y, in thousands, for all crimes other than drug offenses x years after 1998. c. Use the models from parts (a) and (b) to determine in which year the number of federal inmates for drug offenses was the same as the number of federal inmates for all other crimes. How many inmates were there for drug offenses and for all other crimes in that year?

Write a system of equations having {(-2, 7)} as a solution set. (More than one system is possible.)

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