/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 56 Verify each identity. \(\left(... [FREE SOLUTION] | 91Ó°ÊÓ

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Verify each identity. \(\left(\cot ^{2} \theta+1\right)\left(\sin ^{2} \theta+1\right)=\cot ^{2} \theta+2\)

Short Answer

Expert verified
\((\cot ^{2} \theta+1)(\sin ^{2} \theta+1) = \cot ^{2} \theta+2\)

Step by step solution

01

Expand the product

First, expand \((\cot ^{2} \theta+1)(\sin ^{2} \theta+1)\) on the left side of the equation to get: \(\cot ^{2} \theta \sin ^{2} \theta+\cot ^{2} \theta+\sin ^{2} \theta+1\)
02

Simplify Trig terms

Remember the trigonometric identity \(\cot ^{2} \theta = \csc^{2}\theta - 1\), and that \(\csc \theta = \frac{1}{\sin \theta}\). Replace \(\cot ^{2} \theta\) in the expanded expression, and simplify to get: \((\csc^{2}\theta - 1) \sin ^{2} \theta+(\csc^{2}\theta - 1)+\sin ^{2} \theta+1\) = \(1+ \sin ^{2} \theta+\csc^{2}\theta - 1+ \sin ^{2} \theta+1\)
03

Substitute back and simplify

Substituting \(\csc^{2}\theta = \cot^{2}\theta+1\) back into the previous equation we get: \(\cot ^{2} \theta+1+ \sin ^{2} \theta+ \sin ^{2} \theta+1 = \cot ^{2} \theta+2\)
04

Verify the identity

Check if the simplified expression is equal to the right-hand side of the original identity. We find that both the expressions are equal, hence confirming that the trigonometric identity is verified. The right side of the equation is identical to the left side thus confirming that \((\cot ^{2} \theta+1)(\sin ^{2} \theta+1) = \cot ^{2} \theta+2\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cotangent Squared Identity
When studying trigonometric identities, understanding the cotangent squared identity is crucial.
The cotangent squared identity is expressed as:
\[\cot^2\theta = \csc^2\theta - 1\].
Here, \(\csc\theta\) is the cosecant of \(\theta\), which is the reciprocal of sine. In other words, \(\csc\theta = \frac{1}{\sin\theta}\).
The importance of this identity lies in its ability to transform trigonometric expressions and solve trigonometric equations more easily. To see it in action, consider the exercise:
\[(\cot^2\theta + 1)(\sin^2\theta + 1)\].
Using the cotangent squared identity, we can rewrite \(\cot^2\theta\) as \(\csc^2\theta - 1\) and proceed with simplifying the expression. It's the recognition and application of such identities that empower students to tackle more complex trigonometric problems.
Sine Squared Identity
Similarly, the sine squared identity also plays a pivotal role in solving trigonometric equations. Unlike the cotangent squared identity, the sine squared identity often comes in a set known as the Pythagorean identities.
One of the forms is:
\[\sin^2\theta + \cos^2\theta = 1\].
From here, we can derive the sine squared identity as:
\[\sin^2\theta = 1 - \cos^2\theta\].
This allows us to relate the sine function to its complementary cosine function. Understanding this relationship enables students to transition between expressions involving sine and cosine, which is a valuable skill in verifying trigonometric identities. In the given exercise, having knowledge of the sine squared identity wasn't directly necessary, but it emphasizes the interconnectedness of trigonometric functions.
Trigonometric Identity Verification
Verification of trigonometric identities like \((\cot^2\theta + 1)(\sin^2\theta + 1) = \cot^2\theta + 2\) involves a systematic approach. The process starts with familiarizing oneself with fundamental trigonometric identities.
The next step is to expand and simplify the given expressions using these identities, as shown in the exercise solution. This step often necessitates algebraic manipulations such as expanding products or combining like terms.
After simplification, we should arrive at an expression that matches the given identity or proves that the two sides of the equation are equivalent. It is worth noting that during verification, no assumption should be made about the initial validity of the identity—it must be proven through algebraic and trigonometric manipulation alone.
Through practice, the verification of trigonometric identities becomes a routine exercise that reinforces a student's understanding of the trigonometric functions and their relationships.

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Most popular questions from this chapter

Write each trigonometric expression as an algebraic expression (that is, without any trigonometric functions). Assume that x and y are positive and in the domain of the given inverse trigonometric function. $$ \sin \left(\tan ^{-1} x-\sin ^{-1} y\right) $$

When throwing can object, the distance achieved depends on its initial velocity, \(v_{0}\) cand the angle above the horizontal at which the object is thrown, \(\boldsymbol{\theta}\). The distance, \(d,\) in feet, that describes the range covered is given by $$ d=\frac{v_{0}^{2}}{16} \sin \theta \cos \theta $$$$ \text { where } \boldsymbol{\tau}_{0} \text { is measured in feet per second.} $$ You and your friend are throwing a baseball back and forth. If you throw the ball with an initial velocity of \(x_{0}=90\) feet per second, at what angle of elevation, \(\theta\). to the nearest degree, should you direct your throw so that it can be easily caught by your friend located 170 feet away?

Verify each identity. \(\sec x-\sec x \sin ^{2} x=\cos x\)

Use this information to solve: The speed of a supersonic aircraft is usually represented by a Mach number, named after Austrian physicist Ernst Mach \((1838-1916) .\) A Mach number is the speed of the aircraft, in miles per hour, divided by the speed of sound, approximately 740 miles per hour. Thus, a plane flying at twice the speed of sound has a speed, M, of Mach 2. (GRAPH CANNOT COPY). If an aircraft has a speed greater than Mach 1 , a sonic boom is heard, created by sound waves that form a cone with a vertex angle \(\theta,\) shown in the figure. The relationship between the cone's vertex angle, \(\theta,\) and the Mach speed, M, of an aircraft that is flying faster than the speed of sound is given by $$ \sin \frac{\theta}{2}=\frac{1}{M} $$ If \(\theta=\frac{\pi}{6},\) determine the Mach speed, \(M,\) of the aircraft. Express the speed as an exact value and as a decimal to the nearest tenth.

Throwing events in track and field include the shot put, the discus throw, the hammer throw, and the javelin throw. The distance that the athlete can achieve depends on the initial speed of the object thrown and the angle above the horizontal at which the object leaves the hand. This angle is represented by \(\theta\) in the figure shown. The distance, \(d,\) in feet, that the athlete throws is modeled by the formula $$ d=\frac{v_{0}^{2}}{16} \sin \theta \cos \theta $$ in which \(v_{0}\) is the initial speed of the object thrown, in feet per second, and \(\theta\) is the angle, in degrees, at which the object leaves the hand. a. Use an identity to express the formula so that it contains the sine function only. b. Use your formula from part (a) to find the angle, \(\theta,\) that produces the maximum distance, \(d,\) for a given initial speed, \(v_{0}\).

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