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Solve equation by factoring. $$ 10 x-1=(2 x+1)^{2} $$

Short Answer

Expert verified
Hence, the roots of the equation are \(x = 1\) and \(x = 0.5\)

Step by step solution

01

Expand the squared term

Expand the right side of the equation: \( (2x + 1)^{2} \) to give \(4x^{2}+4x+1\). The equation now becomes \(10x - 1 = 4x^{2}+4x+1\)
02

Reorder the equation

Rearrange the equation in a form of \(ax^2 + bx + c = 0\), by subtracting \(10x\) and 1 from both sides: So the equation becomes: \(4x^{2}+4x+1 - 10x +1 = 0\). This simplifies to \(4x^{2} - 6x + 2 = 0\)
03

Factor the quadratic equation

Factor the quadratic equation. Firstly, factor out the greatest common factor if possible. Then factor by grouping, difference of squares, perfect square trinomials, or other methods as required. Unfortunately, this equation isn't factorable. So, neither factoring nor factoring by grouping applies.
04

Solve using the quadratic formula

Since the equation could not be factored, use the quadratic formula which is \(x = [-b \pm \sqrt{(b^{2}-4ac)}]/2a\) where \(a = 4, b = -6, c = 2\) which solves to \(x = [6 \pm \sqrt{(-6)^{2}-4(4)(2)}]/2(4)\) . This simplifies to \(x = [6 \pm \sqrt{36-32}]/8\) which further simplifies to \(x = [6 \pm \sqrt{4}]/8\). Therefore, \(x = [6 \pm 2]/8\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Quadratic Equations
Factoring quadratic equations is a critical skill in algebra that allows students to solve quadratic equations by expressing them as a product of their factors. The equation of a quadratic is typically in the form of \(ax^2 + bx + c = 0\). The goal is to identify two binomials, \((mx + n)(px + q)\), that multiply to give the original quadratic equation. To factor a quadratic:

  • First, look for a greatest common factor (GCF) and factor it out.
  • If no GCF is present or after factoring it out, you will need to find two numbers that multiply to 'ac' and add to 'b'.
  • Rewrite 'bx' as two terms using the numbers found, and then factor by grouping.
  • If the quadratic is a special case, such as a difference of squares or a perfect square trinomial, apply the specific factoring rules that apply to these cases.

It's important to determine if the quadratic is factorable, which might not always be the case. When you encounter an equation like \(4x^{2} - 6x + 2 = 0\), and can't find integers m, n, p, q such that mp = 4, nq = 2 and mn + pq = -6, it indicates that the quadratic equation doesn't factor over the integers and another method, like the quadratic formula, needs to be used. This step is crucial, as it can save time and avoid frustration for students.
Quadratic Formula
When factoring fails, the quadratic formula is a reliable alternative to find the solutions of a quadratic equation. The quadratic formula is given by:

\[x = \frac{{-b \pm \sqrt{{b^2-4ac}}}}{2a}\]
This formula provides the roots of any quadratic equation \(ax^2 + bx + c = 0\), where 'a' is the coefficient of \(x^2\), 'b' the coefficient of x, and 'c' the constant term. The symbol '±' indicates there are generally two solutions. Here's a step-by-step guide to use the formula:

Identify a, b, and c

  • Look at the equation \(4x^{2} - 6x + 2 = 0\) and identify: \(a = 4\), \(b = -6\), and \(c = 2\).

Substitute into the formula

  • Substitute the values into the quadratic formula and calculate the discriminant (\(b^2-4ac\)).
  • If the discriminant is positive, there are two real and distinct solutions. If it is zero, there is one real solution. If it is negative, there are no real solutions (but two complex ones).

Simplify the expression

  • After performing the operations including the square root, divide by \(2a\) to find the solutions.

Students should get comfortable with this formula as it is essential when other methods of solving quadratics are not applicable.
Expand and Simplify Equations
Understanding how to expand and simplify equations is foundational in solving quadratics. Expanding involves multiplying out brackets to write an expression in a simplified form. When you have \((2x + 1)^2\), you would expand this by multiplying the binomial by itself to get \(4x^2 + 4x + 1\). Simplifying an equation is about combining like terms and arranging terms in a standard form, which often leads to solving for unknown variables. The process goes:

Expansion

  • Use the FOIL (First, Outside, Inside, Last) method for binomials or apply the distributive property for more complex expressions.

Simplification

  • Rearrange terms so you can combine like terms (terms with the same variable and exponent).
  • For example, rewrite \(10x - 1\) as \(10x + (-1)\) to easily subtract \(1\) from both sides, combining it with another constant on the other side.
  • Once simplified, the expression can be set to zero in preparation for solving.

Simplifying equations makes them easier to work with and helps students to see the 'clear path' towards the solution, whether by factoring, applying the quadratic formula, or using graphical methods.

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Most popular questions from this chapter

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