Chapter 1: Problem 14
Graph each equation in Exercises \(13-28 .\) Let \(x=-3,-2,-1,0\) \(1,2,\) and 3. $$y=x^{2}+2$$
Short Answer
Expert verified
The graph of \(y = x^{2} + 2\) is a parabola that opens upwards and is shifted upward by 2 units.
Step by step solution
01
Identify the equation type
The equation given is \(y = x^{2}+2\), which is a form of quadratic equation. It describes a parabola that opens upwards, because the coefficient of \(x^2\) is positive.
02
Generate values of y
Use the given x values to substitute into the equation \(y = x^{2}+2\) to generate corresponding y values. For example, if \(x = -3\), then \(y = (-3)^{2} + 2 = 11\). Repeat this for all x values.
03
Plot Graph
Once you have your x and y values calculated, plot them on the graph. Your x-values are \(-3,-2,-1,0,1,2,3\) and your corresponding y-values are results of calculations from Step 2.
04
Draw the Parabola
After plotting the points, connect them to get the shape of a parabola. Remember, the graph of \(y = x^{2} + 2\), where 2 is a constant, will be a parabola that opens upwards because the coefficient of \(x^2\) is positive and the parabola is shifted upwards by 2 units.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola
A parabola is a U-shaped curve that is the graphical representation of a quadratic equation. When you see an equation like \( y = x^2 + 2 \), you're dealing with a parabola. This particular equation has a positive coefficient of \( x^2 \), which means the parabola opens upwards. Think of it like a bowl sitting right side up. It's important to note that the number added to \( x^2 \) (in this case, +2) affects the vertical position of the parabola. So, instead of having the parabola start at the origin (0,0), it shifts up 2 units on the y-axis. This vertical shift helps us easily recognize where the parabola starts on the graph.
Graphing Equations
Graphing equations involves plotting a set of points on a coordinate system based on the relationship between two variables, usually \( x \) and \( y \). When dealing with quadratic equations, like \( y = x^2 + 2 \), graphing helps visualize how changes in \( x \) affect \( y \). First, identify the equation's type, here quadratic, which gives a parabolic graph. Begin by choosing some x-values to substitute into your equation. These will help generate corresponding y-values. This conversion of an equation to a visual can simplify complex relationships and make comparisons easier. The regularity of the pattern generated by a quadratic equation, with its curved shape, helps to confirm the accuracy of your plot.
X-Values and Y-Values
X-values and y-values are crucial in graphing equations because they represent the coordinates of points on the graph. For an equation like \( y = x^2 + 2 \), the x-values are independent variables: the inputs you choose. The original exercise lists x-values as \(-3, -2, -1, 0, 1, 2, 3\). When these are plugged into the quadratic equation, they yield y-values, such as \( y = (-3)^2 + 2 = 11 \). Each pair (x, y) forms a point that can be plotted on the graph. By calculating more (x, y) pairs, you can outline the shape of the curve accurately. Collectively, these points provide a detailed picture of how the quadratic equation behaves.
Plotting Points
Plotting points is where the magic happens in turning equation solutions into visual graphs. After calculating the x-values and their corresponding y-values, the next step is to mark these points on a coordinate plane. For each pair, plot the point by moving horizontally to the x-value and vertically to the y-value. For instance, with x-value -3 and y-value 11, you’d place a point on the graph at (-3, 11). Ensure precision to correctly display the smooth curve of the parabola. Once all points are plotted, they can be connected to reveal the parabolic shape. This is a crucial step as it lays the groundwork for interpreting the behavior and characteristics of the equation graphically.