Chapter 1: Problem 139
Will help you prepare for the material covered in the next section. Solve: \(\frac{x+3}{4}=\frac{x-2}{3}+\frac{1}{4}\)
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Chapter 1: Problem 139
Will help you prepare for the material covered in the next section. Solve: \(\frac{x+3}{4}=\frac{x-2}{3}+\frac{1}{4}\)
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A machine produces open boxes using square sheets of metal. The machine cuts equal-sized squares measuring 3 inches on a side from the corners and then shapes the metal into an open box by turning up the sides. If each box must have a volume of 75 cubic inches, find the length and width of the open box.
In Exercises 142–143, solve each inequality using a graphing utility. Graph each side separately. Then determine the values of x for which the graph for the left side lies above the graph for the right side. $$ -3(x-6)>2 x-2 $$
Each side of a square is lengthened by 2 inches. The area of this new, larger square is 36 square inches. Find the length of a side of the original square.
In Exercises 95–102, use interval notation to represent all values of x satisfying the given conditions. \(y=1-(x+3)+2 x\) and \(y\) is at least 4
When the sum of 6 and twice a positive number is subtracted from the square of the number, 0 results. Find the number.
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