Chapter 5: Problem 49
Solve the logarithmic equation for \(x.\) \(\log _{5}(x+1)-\log _{5}(x-1)=2\)
Short Answer
Expert verified
\(x = \frac{13}{12}\)
Step by step solution
01
Use the Quotient Rule for Logarithms
The equation \( \log_{5}(x+1) - \log_{5}(x-1) = 2 \) allows us to use the quotient rule of logarithms. This rule states \( \log_{b}(A) - \log_{b}(B) = \log_{b}\left(\frac{A}{B}\right) \). Apply this rule to get \( \log_{5}\left(\frac{x+1}{x-1}\right) = 2 \).
02
Convert Logarithmic Equation to Exponential Form
The equation \( \log_{5}\left(\frac{x+1}{x-1}\right) = 2 \) can be rewritten in exponential form. This gives \( \frac{x+1}{x-1} = 5^{2} \), which simplifies to \( \frac{x+1}{x-1} = 25 \).
03
Solve the Proportion for \(x\)
Set the equation \( \frac{x+1}{x-1} = 25 \) as a proportion and solve for \( x \). Cross-multiply to get \( x+1 = 25(x-1) \). Then distribute on the right to get \( x+1 = 25x - 25 \).
04
Isolate \(x\)
Rearrange the equation \( x+1 = 25x - 25 \) to isolate \( x \). Subtract \( x \) from each side to get \( 1 = 24x - 25 \), then add 25 to both sides to get \( 26 = 24x \).
05
Divide to Find \(x\)
To solve for \( x \), divide both sides by 24: \( x = \frac{26}{24} \). Simplify to get \( x = \frac{13}{12} \).
06
Verify the Solution
Verify that \( x = \frac{13}{12} \) satisfies the original equation \( \log_{5}(x+1) - \log_{5}(x-1) = 2 \). When substituting back into the equation, both sides should evaluate to 2, confirming the solution is correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quotient Rule of Logarithms
The quotient rule of logarithms is a powerful tool that simplifies logarithmic expressions involving subtraction. This rule states that for the same base, the difference of two logarithms is equivalent to a single logarithm with a quotient of the arguments. Mathematically, it is expressed as: \[ \log_{b}(A) - \log_{b}(B) = \log_{b}\left(\frac{A}{B}\right) \]In the original exercise, the equation \( \log_{5}(x+1) - \log_{5}(x-1) = 2 \) applied the quotient rule. This combined the two separate logarithms into one:
- \( \log_{5}\left(\frac{x+1}{x-1}\right) = 2 \)
Exponential Form
Converting a logarithmic equation to its exponential form is essential in solving equations involving logarithms. Remember, a logarithmic expression \( \log_{b}(A) = C \) can be transformed into an exponential form as \( A = b^{C} \). In the given problem, the equation transformed into exponential form is:
- \( \log_{5}\left(\frac{x+1}{x-1}\right) = 2 \) becomes \( \frac{x+1}{x-1} = 5^{2} \)
Proportion
After converting the logarithmic expression to an exponential form, you encounter a proportion, a mathematical equation that states two ratios or fractions are equivalent. In this scenario, \( \frac{x+1}{x-1} = 25 \).To solve this proportion, cross-multiplication is used, which involves multiplying the numerator of one fraction by the denominator of the other and vice-versa. The steps are as follows:
- Cross-multiply: \( x+1 = 25(x-1) \)
- Distribute the 25: \( x+1 = 25x - 25 \)