Chapter 5: Problem 21
\(17-24\) . These exercises use the radioactive decay model. Finding Half-life If 250 \(\mathrm{mg}\) of a radioactive element de- cays to 200 \(\mathrm{mg}\) in 48 hours, find the half-life of the element.
Short Answer
Expert verified
The half-life of the element is approximately 142 hours.
Step by step solution
01
Understanding the Decay Model
The radioactive decay model follows the formula \( N(t) = N_0 \cdot e^{-kt} \), where \( N(t) \) is the amount remaining at time \( t \), \( N_0 \) is the initial amount, and \( k \) is the decay constant.
02
Set Up the Equation with Given Values
We start with \( N_0 = 250 \text{ mg} \) and after 48 hours, \( N(48) = 200 \text{ mg} \). Insert these values into the decay equation: \( 200 = 250 \cdot e^{-48k} \).
03
Solve for the Decay Constant \( k \)
Divide both sides by 250 to isolate the exponential expression: \( \frac{200}{250} = e^{-48k} \), simplifying to \( 0.8 = e^{-48k} \).
04
Take the Natural Logarithm
Apply the natural logarithm to both sides to solve for \( k \): \( \ln(0.8) = -48k \).
05
Solve for \( k \)
Calculate \( k \) by dividing both sides by \(-48\): \( k = \frac{\ln(0.8)}{-48} \).
06
Calculate Half-Life Using \( k \)
The half-life \( t_{1/2} \) can be calculated using the formula \( t_{1/2} = \frac{\ln(2)}{k} \). Substitute the value of \( k \) calculated from Step 5 into this formula to find the half-life.
07
Final Calculation
Compute \( k \) from the natural log equation and then substitute it back to calculate \( t_{1/2} \). After calculation, the half-life of the element is approximately 142 hours.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-Life
The concept of half-life is fundamental in understanding radioactive decay. It refers to the time it takes for half of a given amount of a radioactive substance to disintegrate. For a radioactive element with a short half-life, you can expect that it will decay quickly. Conversely, if the half-life is long, the decay process will proceed slowly. This property is crucial in fields like archaeology and medicine, where knowing how fast a substance decays can inform dating or treatment decisions.
The formula for calculating the half-life, denoted as \( t_{1/2} \), is\[t_{1/2} = \frac{\ln(2)}{k}\]where \( k \) is the decay constant. Understanding this formula allows you to calculate how long it would take for a specified amount of a substance to decrease by 50%. When we say a substance has a certain half-life, it implies that, over that period, only half of the original substance remains.
The formula for calculating the half-life, denoted as \( t_{1/2} \), is\[t_{1/2} = \frac{\ln(2)}{k}\]where \( k \) is the decay constant. Understanding this formula allows you to calculate how long it would take for a specified amount of a substance to decrease by 50%. When we say a substance has a certain half-life, it implies that, over that period, only half of the original substance remains.
Decay Constant
In radioactive decay, the decay constant \( k \) plays a pivotal role. It is a number that expresses the rate at which a substance undergoes radioactive decay. This constant is unique to each radioactive isotope, effectively capturing its inherent instability. A larger decay constant means a rapid decay, which translates to a shorter half-life, and vice versa.
To determine \( k \), you often use data from measurements of the substance's decay over time. As seen in our exercise, \[ k = \frac{\ln(0.8)}{-48}\]was derived from observing the reduction in mass from 250 mg to 200 mg over 48 hours. By knowing \( k \), you can predict how quickly an isotope will decrease under given conditions, making it an invaluable variable in predictive calculations of radioactive decay.
To determine \( k \), you often use data from measurements of the substance's decay over time. As seen in our exercise, \[ k = \frac{\ln(0.8)}{-48}\]was derived from observing the reduction in mass from 250 mg to 200 mg over 48 hours. By knowing \( k \), you can predict how quickly an isotope will decrease under given conditions, making it an invaluable variable in predictive calculations of radioactive decay.
Exponential Decay
Radioactive decay is a classic example of exponential decay, which is a process describing quantities that decrease at a rate proportional to their current value. In simpler terms, the more you have, the faster it goes. The formula used is\[N(t) = N_0 \cdot e^{-kt}\]where \( N(t) \) is the remaining amount at time \( t \), \( N_0 \) is the initial amount, and \( e \) is the base of the natural logarithm.
This specific pattern is characterized by a swift early decline that gradually slows down. Understanding exponential decay helps in predicting how a certain amount of a substance reduces over time, which is exactly what we achieved in the step-by-step solution. This formula tells us how much of a substance remains after a certain period, given its decay constant.
This specific pattern is characterized by a swift early decline that gradually slows down. Understanding exponential decay helps in predicting how a certain amount of a substance reduces over time, which is exactly what we achieved in the step-by-step solution. This formula tells us how much of a substance remains after a certain period, given its decay constant.
Natural Logarithm
The natural logarithm, denoted as \( \ln \), is critical in the mathematics of radioactive decay. It provides a method to solve for the time or decay constant in radioactive decay formulas. The natural logarithm is based on the mathematical constant \( e \), approximately equal to 2.71828. In our example, taking the natural log of both sides of the equation was key to isolating and calculating \( k \).
- The natural logarithm helps transition from an exponential equation to a linear one.
- Its properties enable direct solving of exponential decay equations.