/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Five independent trials of a bin... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Five independent trials of a binomial experiment with probability of success \(p=0.7\) and probability of failure \(q=0.3\) are performed. Find the probability of each event. At least three successes

Short Answer

Expert verified
The probability of at least three successes is approximately 0.83692.

Step by step solution

01

Understand the Problem

We are dealing with a binomial distribution with parameters: number of trials \( n = 5 \), probability of success \( p = 0.7 \), and probability of failure \( q = 1 - p = 0.3 \). We are looking for the probability of getting at least three successes in five trials.
02

Define the Cumulative Probability

The probability of at least three successes can be expressed as the sum of probabilities of exactly three, four, and five successes. In mathematical terms, this is \( P(X \geq 3) = P(X = 3) + P(X = 4) + P(X = 5) \).
03

Calculate the Probability for Exactly Three Successes

Use the binomial probability formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]Substitute \( n = 5 \), \( k = 3 \), \( p = 0.7 \), so:\[ P(X = 3) = \binom{5}{3} (0.7)^3 (0.3)^{5-3} = 10 \times 0.343 \times 0.09 = 0.3087 \]
04

Calculate the Probability for Exactly Four Successes

Using the binomial formula with \( k = 4 \): \[ P(X = 4) = \binom{5}{4} (0.7)^4 (0.3)^{5-4} = 5 \times 0.2401 \times 0.3 = 0.36015 \]
05

Calculate the Probability for Exactly Five Successes

Using the binomial formula with \( k = 5 \): \[ P(X = 5) = \binom{5}{5} (0.7)^5 (0.3)^{5-5} = 1 \times 0.16807 \times 1 = 0.16807 \]
06

Sum the Probabilities for At Least Three Successes

Add the probabilities for exactly three, four, and five successes:\[ P(X \geq 3) = P(X = 3) + P(X = 4) + P(X = 5) = 0.3087 + 0.36015 + 0.16807 = 0.83692 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability of Success
In a binomial experiment, the probability of success is a key concept to grasp. It is denoted by the symbol \( p \) and represents the likelihood of achieving the desired outcome in a single trial. For each attempt, this probability remains constant, which is an essential characteristic of binomial distributions.
Understanding \( p \) helps us determine how likely it is to achieve a certain number of successes over multiple trials. For example, if the probability of success \( p \) is 0.7, as in the given problem, it means there is a 70% chance of success in each trial.
  • This value impacts the calculations of individual event probabilities.
  • It influences the overall shape of the distribution.
The probability of success, together with the probability of failure \( q \) (where \( q = 1 - p \)), ensures that each trial totals to a certainty of 100%.
Binomial Probability Formula
The binomial probability formula is a crucial tool for calculating the probability of a specific number of successes in a series of independent Bernoulli trials. The formula is expressed as follows: \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \). Here, the parameters represent:
  • \( n \): The total number of trials.
  • \( k \): The number of successes we are interested in.
  • \( \binom{n}{k} \): The number of combinations of \( n \) items taken \( k \) at a time, calculated by \( \frac{n!}{k!(n-k)!} \).
  • \( p \): The probability of success in a single trial.
  • \( 1-p \): The probability of failure.
This formula allows us to determine the exact likelihood of achieving exactly \( k \) successes in \( n \) trials. For instance, in the given scenario, you calculated the probability for exactly three, four, and five successes using this method.
Cumulative Probability
Cumulative probability helps us understand the likelihood of achieving a range of outcomes. Instead of calculating the probability for a single event, it sums the probabilities for multiple events.
In the context of the problem, you are interested in the probability of achieving at least three successes in five trials. This is an example of cumulative probability, seeking the probability for \( P(X \geq 3) \).
  • To find \( P(X \geq 3) \), add the individual probabilities of achieving exactly three, four, and five successes:
  • \( P(X = 3) + P(X = 4) + P(X = 5) \)
This approach is practical because it allows us to understand the likelihood of a sum of different event outcomes within a particular range. Cumulative probability is particularly useful in scenarios where "at least" or "at most" types of questions are involved. This gives a complete picture of the chances for multiple outcomes at once, providing deeper insights into the problem at hand.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve the problem using the appropriate counting principle(s). Choosing a Pizza A pizza parlor offers four sizes of pizza (small, medium, large, and colossus), two types of crust (thick and thin), and 14 different toppings. How many different pizzas can be made with these choices?

Genders of Children The ratio of male to female births is in fact not exactly one-to-one. The probability that a newborn turns out to be a male is about \(0.52 .\) A family has ten children. (a) What is the probability that all ten children are boys? (b) What is the probability all are girls? (c) What is the probability that five are girls and five are boys?

Hitting a Target An archer normally hits the target with probability of \(0.6 .\) She hires a new coach for a series of special lessons. After the lessons she hits the target in five out of eight attempts. (a) Find the probability that she would have hit five or more out of the eight attempts before her lessons with the new coach. (b) Did the new coaching effective if the probability in part (a) is 0.05 or less.)

Quality Control An assembly line that manufactures fuses for automotive use is checked every hour to ensure the quality of the finished product. Ten fuses are selected randomly, and if any one of the ten is found to be defective, the process is halted and the machines are recalibrated. Suppose that at a certain time 5\(\%\) of the fuses being produced are actually defective. What is the probability that the assembly line is halted at that hour's quality check?

Committee Membership A mathematics department consists of ten men and eight women. Six mathematics faculty members are to be selected at random for the curriculum committee. (a) What is the probability that two women and four men are selected? (b) What is the probability that two or fewer women are selected? (c) What is the probability that more than two women are selected?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.