Chapter 1: Problem 56
Evaluate the radical expression, and express the result in the form \(a+b i\) $$ \frac{\sqrt{-7} \sqrt{-49}}{\sqrt{28}} $$
Short Answer
Expert verified
The expression simplifies to \(-\frac{7}{2} + 0i\).
Step by step solution
01
Simplify the radicals in the numerator
Start by evaluating the product of the radicals in the numerator. Since \( \sqrt{-7} \cdot \sqrt{-49} = \sqrt{(-7) imes (-49)} \), we have \( \sqrt{343} \). Additionally, remember that \( \sqrt{-1} = i \), so \( \sqrt{-7} = \sqrt{7} i \) and \( \sqrt{-49} = 7i \). Multiply these, \( (\sqrt{7} \cdot 7) i^2 = -7\sqrt{7} \). So, the numerator simplifies to \(-7 \sqrt{7}\).
02
Simplify the denominator
Identify \( \sqrt{28} \). The number 28 can be factored into \( 4 \times 7 \), so \( \sqrt{28} = \sqrt{4 \times 7} = \sqrt{4} \cdot \sqrt{7} = 2\sqrt{7} \). The denominator simplifies to \( 2\sqrt{7} \).
03
Divide the numerator by the denominator
Take the simplified numerator \(-7 \sqrt{7}\) and divide it by the simplified denominator \(2\sqrt{7}\). This gives \( \frac{-7\sqrt{7}}{2\sqrt{7}} \). Simplifying, since \( \sqrt{7} \) cancels out, the expression becomes \( -\frac{7}{2} \).
04
Express the result in terms of a complex number
The division resulted in a purely real number \( -\frac{7}{2} \), which can be expressed in the form \( a + bi \) as \( -\frac{7}{2} + 0i \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Radical Expressions
Radical expressions involve roots, which are mathematical relationships indicating how many times a number must be multiplied by itself to achieve another number. The most common radical is the square root, represented as \( \sqrt{} \). In the given exercise, the goal is to evaluate a complex radical expression. We begin by simplifying radicals in the expression \( \frac{\sqrt{-7} \sqrt{-49}}{\sqrt{28}} \). When tackling radical expressions, remember to simplify them to a form that is easier to work with. For example:
- The square root of a negative number can be expressed using \( i \), since \( \sqrt{-1} = i \).
- Combine the radicands (numbers inside the square root) when possible to further simplify the expression.
Imaginary Unit
The imaginary unit, denoted by \( i \), is what allows us to work with square roots of negative numbers. The definition of \( i \) is \( \sqrt{-1} \). This is crucial because it helps simplify expressions like \( \sqrt{-7} \) and \( \sqrt{-49} \) in our problem. Here is how it applies:
- Since \( \sqrt{-7} = \sqrt{7} \cdot i \), the negative under the root is managed by the \( i \).
- Similarly, \( \sqrt{-49} = 7i \) because \( 49 \) is a perfect square but is negatively signed.
Complex Form a + bi
Complex numbers are expressed in the form \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) represents the imaginary unit. In the exercise, the answer was eventually simplified to a real number \( -\frac{7}{2} \), expressed as \( -\frac{7}{2} + 0i \). This representation shows that complex numbers can be comprised entirely of real numbers with an imaginary part of zero:
- \( a \) is the real component, determining the position on the horizontal axis of the complex plane.
- \( bi \) is the imaginary component, indicating placement on the vertical axis.