Chapter 9: Problem 86
Find the indicated roots, and graph the roots in the complex plane. The fifth roots of \(-16-16 \sqrt{3} i\)
Short Answer
Expert verified
The fifth roots are 2cis(4Ï€/15), 2cis(10Ï€/15), 2cis(16Ï€/15), 2cis(22Ï€/15), and 2cis(28Ï€/15).
Step by step solution
01
Express Complex Number in Polar Form
First, express the complex number \(-16 - 16\sqrt{3}i\) in polar form. To do this, we need to find the magnitude \(r\) and the argument \(\theta\). The magnitude is calculated as \(r = \sqrt{(-16)^2 + (-16\sqrt{3})^2} = \sqrt{256 + 768} = 32\). To find \(\theta\), use the tangent function: \(\tan\theta = \frac{\text{Imaginary part}}{\text{Real part}} = \frac{-16\sqrt{3}}{-16} = \sqrt{3}\), which means \(\theta = \frac{4\pi}{3}\) (in the third quadrant). Therefore, in polar form it is \(32\text{cis}\frac{4\pi}{3}\).
02
Apply De Moivre's Theorem for Roots
To find the fifth roots, apply De Moivre's Theorem. The roots are given by:\[ z_k = 32^{1/5} \text{cis} \left( \frac{\frac{4\pi}{3} + 2k\pi}{5} \right) \] for \(k = 0, 1, 2, 3, 4\). Here, \(32^{1/5} = 2\).
03
Calculate Each Root
Calculate the argument for each root:- For \(k = 0\), \(z_0 = 2\text{cis} \left( \frac{4\pi}{15} \right) \)- For \(k = 1\), \(z_1 = 2\text{cis} \left( \frac{10\pi}{15} \right) \)- For \(k = 2\), \(z_2 = 2\text{cis} \left( \frac{16\pi}{15} \right) \)- For \(k = 3\), \(z_3 = 2\text{cis} \left( \frac{22\pi}{15} \right) \)- For \(k = 4\), \(z_4 = 2\text{cis} \left( \frac{28\pi}{15} \right) \)
04
Graph the Roots in the Complex Plane
Plot each of the roots extracted from polar form, using the magnitudes and arguments calculated in Step 3. Each root is a point in the complex plane at distance 2 from the origin, with angles corresponding to their calculated arguments. The points will be equally distributed around a circle of radius 2, centered at the origin.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
De Moivre's Theorem
De Moivre's Theorem is a powerful formula used in complex number operations, especially when raising complex numbers to powers or finding roots. It states:
\[ (r \text{cis} \theta)^n = r^n \text{cis} (n\theta) \]
Here, "cis" stands for \(\cos \theta + i \sin \theta\), which is a shorthand used in trigonometry for ease. When dealing with roots, De Moivre's Theorem allows us to find multiple solutions by taking the \(n\)-th root of the magnitude \(r\) and adjusting the angle \(\theta\) accordingly.
- To find the \(n\)-th roots using De Moivre's Theorem:
\[ (r \text{cis} \theta)^n = r^n \text{cis} (n\theta) \]
Here, "cis" stands for \(\cos \theta + i \sin \theta\), which is a shorthand used in trigonometry for ease. When dealing with roots, De Moivre's Theorem allows us to find multiple solutions by taking the \(n\)-th root of the magnitude \(r\) and adjusting the angle \(\theta\) accordingly.
- To find the \(n\)-th roots using De Moivre's Theorem:
- Determine \(r^{1/n}\), the \(n\)-th root of the magnitude.
- Calculate the angle: divide the original angle by \(n\) and consider adding \(\frac{2k\pi}{n}\) for \(k = 0, 1, ..., n-1\).
Polar Form
The polar form of a complex number provides a fascinating way to understand and manipulate it, especially when using trigonometric identities and performing multiplications or divisions. A complex number \(a + bi\) can be transformed into polar form as \(r \text{cis} \theta\).
- To convert to polar form:
- To convert to polar form:
- Find the magnitude \(r\) using \(\sqrt{a^2 + b^2}\).
- Determine the angle \(\theta\) using \(\tan \theta = \frac{b}{a}\).
Complex Plane Graphing
Graphing in the complex plane offers a visual insight into the nature and behavior of complex numbers. The complex plane is a two-dimensional plane where each point represents a complex number. The horizontal axis (real axis) corresponds to the real part, and the vertical axis (imaginary axis) corresponds to the imaginary part.
- Key points when graphing:
- Key points when graphing:
- Each complex number is a point: \((a, b)\) for \(a + bi\).
- Roots of an equation or expression can create symmetrical patterns such as polygons.
- The angle from the positive real axis, heading counter-clockwise, represents the argument of the number.