Chapter 2: Problem 18
Find an equation of the line that satisfies the given conditions. Through \((-3,-5) ; \quad\) slope \(-\frac{7}{2}\)
Short Answer
Expert verified
The equation is \( y = -\frac{7}{2}x - \frac{31}{2} \).
Step by step solution
01
Understand the Formula
The equation of a line in slope-intercept form is given by \( y = mx + b \), where \( m \) represents the slope and \( b \) the y-intercept. We are provided with a point and a slope, and we will utilize these to find the equation.
02
Use Point-Slope Form
The point-slope form of the equation of a line is \( y - y_1 = m(x - x_1) \). Given point \((-3, -5)\) and slope \( m = -\frac{7}{2} \), substitute these values into the formula: \( y - (-5) = -\frac{7}{2}(x - (-3)) \). This simplifies to \( y + 5 = -\frac{7}{2}(x + 3) \).
03
Simplify the Equation
Distribute \(-\frac{7}{2}\) through the terms in the parentheses: \( y + 5 = -\frac{7}{2}x - \frac{21}{2} \).
04
Solve for y
To convert to slope-intercept form, solve for \( y \) by subtracting 5 from both sides: \( y = -\frac{7}{2}x - \frac{21}{2} - 5 \).
05
Simplify Further
Combine the constants on the right side: \( -\frac{21}{2} - 5 \) can be rewritten as \( -\frac{21}{2} - \frac{10}{2} = -\frac{31}{2} \). This provides us the final equation, \( y = -\frac{7}{2}x - \frac{31}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
The slope-intercept form of a linear equation is a widely used representation because it easily shows the slope and y-intercept of a line. This form is set up as \( y = mx + b \), where:
To transform an equation from point-slope to slope-intercept form, we solve for \( y \). After inserting the given slope and calculating the intercept, a clear linear equation emerges, ready for graphing or further analysis.
- \( m \) is the slope of the line, indicating its steepness and direction.
- \( b \) is the y-intercept, the point where the line crosses the y-axis.
To transform an equation from point-slope to slope-intercept form, we solve for \( y \). After inserting the given slope and calculating the intercept, a clear linear equation emerges, ready for graphing or further analysis.
Point-Slope Form
When you're given a point and a slope, the point-slope form provides a straightforward way to construct the equation of a line. It is expressed as \( y - y_1 = m(x - x_1) \), where:
- \((x_1, y_1)\) are the coordinates of a specific point the line passes through.
- \( m \) is, as always, the slope.
Linear Equations
Linear equations describe a straight line on a plane and are foundational in algebra. They typically combine constants and variables, forming equations that represent a direct relationship between two quantities.
In their basic forms, such as the slope-intercept (\( y = mx + b \)) and point-slope (\( y - y_1 = m(x - x_1) \)), linear equations provide vital information about the geometric entities they describe.
In their basic forms, such as the slope-intercept (\( y = mx + b \)) and point-slope (\( y - y_1 = m(x - x_1) \)), linear equations provide vital information about the geometric entities they describe.
- They show the relationship between two variables, often depicting real-world problems like speed versus time or cost versus quantity.
- Understanding how to manipulate these equations, whether by changing forms or solving for specific variables, is crucial for applying algebra effectively.