/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Colossus Added to Six Flags St. ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Colossus Added to Six Flags St. Louis in \(1986,\) the Colossus is a giant Ferris wheel. Its diameter is 165 feet; it rotates at a rate of about 1.6 revolutions per minute; and the bottom of the wheel is 15 feet above the ground. Find a function that relates a rider's height \(h\) above the ground at time \(t\). Assume the passenger begins the ride at the bottom of the wheel.

Short Answer

Expert verified
The height function is \[ h(t) = 97.5 + 82.5 \cos \left( 3.2 \pi t - \frac{\text{pi}}{2} \right). \]

Step by step solution

01

- Identify the components of the Ferris wheel

The first thing to note is the diameter of the Ferris wheel, which is 165 feet. This means the radius is half of the diameter, so the radius is \(\frac{165}{2} = 82.5\) feet. The bottom of the wheel is 15 feet above the ground.
02

- Determine the vertical displacement

Let's denote the vertical displacement of a passenger above the center of the Ferris wheel as \(d \). The total height of the rider will be this vertical displacement plus the height of the center of the wheel above the ground, which is the sum of the radius and the bottom's height: \(\text{Center's height} = 82.5 + 15 = 97.5\) feet.
03

- Find the angular position function

The Ferris wheel rotates at a rate of 1.6 revolutions per minute. Therefore, the angular speed in radians per minute is \(\theta(t) = 1.6 \times 2\text{pi} t = 3.2 \text{pi} t\), where \(t\) is the time in minutes.
04

- Set up the height function

The height \(h\) of the rider above the ground as a function of time can be modeled using a cosine function since the motion is circular. The general height function will be: \(\text{Height} = 97.5 + 82.5 \cos(3.2 \frac{\text{pi}}{\text{rev}} t)\).
05

- Adjust for starting position

Since the passenger starts at the bottom of the Ferris wheel, the \(\text{cos}\) function must be shifted. Initially at \(t = 0\), \(\text{Height} = 15\), thus we use \(\theta(t) = - \frac{\text{pi}}{2} + 3.2 \frac{\text{pi}}{\text{rev}} t\).
06

- Simplify to obtain the final function

Finally, combine all the pieces into one equation: \[ h(t) = 97.5 + 82.5 \cos \left( 3.2 \pi t - \frac{\text{pi}}{2} \right). \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Functions
Trigonometric functions are fundamental in modeling periodic phenomena, such as the motion of a rider on a Ferris wheel. In this case, we're using the cosine function to describe the height of a rider over time.

The cosine function is particularly useful because it starts at its maximum value when the angle is zero, and it smoothly transitions through all other values in its cycle. This makes it ideal for describing the smooth circular motion of a Ferris wheel.

To understand how we derive the height function, you need to recognize that the height varies sinusoidally (in waves) as the wheel spins. Importantly, the parameters we use in our cosine function (amplitude, period, phase shift) closely relate to the dimensions and speed of the Ferris wheel.
Angular Speed
Angular speed refers to how quickly an object is rotating and is measured in radians per unit time. In this exercise, the Ferris wheel's angular speed is given in revolutions per minute.

To convert it to a more mathematical form, we use the fact that one revolution is equal to \(2\pi\) radians. Thus, if the wheel rotates at 1.6 revolutions per minute, we can express this as:
  • \(1.6 \times 2\pi = 3.2\pi\) radians per minute.
This angular speed tells us how fast the angle in our trigonometric functions changes over time. When plugged into our height equation, it ensures that the rider’s height is accurately modeled throughout the wheel's rotation.
Cosine Function
The cosine function is pivotal in this height calculation due to its properties and shape. Given by \( \text{cos}(\theta) \), its values oscillate between -1 and 1.

Here, we adjust the standard cosine function to match the Ferris wheel's specifics. The formula
  • \( h(t) = 97.5 + 82.5 \cos (3.2 \pi t - \frac{\pi}{2}) \)
helps us map a rider's height. Key adjustments in the formula include:
  • Amplitude: The 82.5 feet represent the amplitude – the maximum extent of vertical displacement from the center.
  • Vertical Shift: The 97.5 term shifts the entire cosine curve upwards so that the lowest point is 15 feet above ground.
  • Phase Shift: The \( - \frac{\pi}{2} \) adjusts the phase of the wave to account for the starting position.
These adjustments ensure our height function accurately represents the motion of the rider from start to end.
Circular Motion
Circular motion involves any motion that makes a circular path at a constant distance from a center point. In the context of our Ferris wheel problem, the rider's circular motion means their height varies in a predictable way over time.

Grasping the nature of circular motion helps understand the importance of trigonometric functions in modeling it. As the wheel turns, every point on its circumference, including where the rider sits, moves up and down in a smooth wave-like motion.

This is precisely why we use cosine. Its periodic nature aligns well with the continuous, repeating nature of circular motion. By tracking the angular position and relating it to vertical displacement through cosine, we effectively map how the rider’s height changes dynamically.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Coast Guard Station Able is located 150 miles due south of Station Baker. A ship at sea sends an SOS call that is received by each station. The call to Station Able indicates the bearing of the ship is \(\mathrm{N} 55^{\circ} \mathrm{E} ;\) the call to Station Baker indicates the bearing of the ship is \(\mathrm{S} 60^{\circ} \mathrm{E}\). (a) How far is each station from the ship? (b) If a helicopter capable of flying 200 miles per hour is dispatched from the station nearest the ship, how long will it take to reach the ship?

In Problems 7-10, an object attached to a coiled spring is pulled down a distance a from its rest position and then released. Assuming that the motion is simple harmonic with period T, find a function that relates the displacement d of the object from its rest position after t seconds. Assume that the positive direction of the motion is up. $$ a=5 ; \quad T=2 \text { seconds } $$

State the formula for finding the area of an SAS triangle in words.

The Bermuda Triangle is roughly defined by Hamilton, Bermuda; San Juan, Puerto Rico; and Fort Lauderdale, Florida. The distances from Hamilton to Fort Lauderdale, Fort Lauderdale to San Juan, and San Juan to Hamilton are approximately \(1028,1046,\) and 965 miles, respectively. Ignoring the curvature of Earth, approximate the area of the Bermuda Triangle.

Tuning Fork The end of a tuning fork moves in simple harmonic motion described by the function \(d(t)=a \sin (\omega t)\) If a tuning fork for the note A above middle \(\mathrm{C}\) on an even-tempered scale \(\left(A_{4},\right.\) the tone by which an orchestra tunes itself) has a frequency of 440 hertz (cycles per second), find \(\omega\). If the maximum displacement of the end of the tuning fork is 0.01 millimeter, find a function that describes the movement of the tuning fork.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.