/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 Tuning Fork The end of a tuning ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Tuning Fork The end of a tuning fork moves in simple harmonic motion described by the function \(d(t)=a \sin (\omega t)\) If a tuning fork for the note A above middle \(\mathrm{C}\) on an even-tempered scale \(\left(A_{4},\right.\) the tone by which an orchestra tunes itself) has a frequency of 440 hertz (cycles per second), find \(\omega\). If the maximum displacement of the end of the tuning fork is 0.01 millimeter, find a function that describes the movement of the tuning fork.

Short Answer

Expert verified
\[ d(t) = 0.01 \sin (880 \pi t) \]

Step by step solution

01

Understand the Given Function

The motion of the tuning fork is described by the function: \[ d(t) = a \sin (\omega t) \]where \(d(t)\) is the displacement at time \(t\), \(a\) is the maximum displacement (amplitude), and \(\omega\) is the angular frequency.
02

Find Angular Frequency (\(\omega\))

The relationship between the frequency \(f\) and the angular frequency \(\omega\) is given by: \[ \omega = 2 \pi f \]Given the frequency of the tuning fork is 440 Hz, substitute \(f = 440\) into the equation: \[ \omega = 2 \pi \times 440 \]Calculate \(\omega\): \[ \omega = 880 \pi \]
03

Identify the Amplitude (\(a\))

The maximum displacement of the tuning fork is given as 0.01 millimeters. Thus, the amplitude \(a\) is: \[ a = 0.01 \text{ mm} \]
04

Write the Function

With \(a = 0.01\) millimeters and \(\omega = 880 \pi\), substitute these values into the function: \[ d(t) = 0.01 \sin (880 \pi t) \]This is the function that describes the movement of the tuning fork.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Frequency
Angular frequency, represented by \(\omega\), is a key concept in simple harmonic motion. It depicts how quickly the oscillation occurs. Unlike the typical frequency, which counts the number of oscillations per second, angular frequency tells us how many radians per second an object oscillating in simple harmonic motion will cover. For a tuning fork vibrating at 440 Hz, we calculate angular frequency using the relationship: \[ \omega = 2 \pi f \] Here, \(f\) is the regular frequency in hertz (Hz). Given that \(f = 440\), we can find \(\omega\): \[ \omega = 2 \pi \times 440 = 880 \pi \] So, the angular frequency for this tuning fork is \880\pi, or approximately \2764\ \text{radians per second}\.
Amplitude
Amplitude, denoted by \(\text{a}\) in our equation, is another crucial concept in simple harmonic motion. Amplitude is the maximum displacement from the equilibrium position during oscillation. For the given tuning fork, it's given that the maximum displacement, or amplitude, is 0.01 millimeters. This value indicates how far the end of the tuning fork moves from its central position at maximum oscillation. In mathematical terms, amplitude does not affect the frequency but defines the peak value of displacement in the function \[ d(t) = a \sin (\omega t) \] So, if \(a = 0.01\mm\), the tuning fork's motion is stretched within this range.
Frequency
Frequency, symbolized by \(\text{f}\), measures how many cycles of oscillation occur per second. In the context of the tuning fork problem, the frequency is 440 Hz, indicating that the tuning fork completes 440 cycles every second. This is a crucial value because it determines the pitch of the sound produced by the fork. Frequency is related to angular frequency \(\omega \) by the equation: \[ \omega = 2 \pi f \] You can see that knowing the frequency helps directly in calculating other phenomena in harmonic motion, such as angular frequency. In our case, since \403Hz \, the angular frequency turns out to be \880 \pi\.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Tuning Fork The end of a tuning fork moves in simple harmonic motion described by the function \(d(t)=a \sin (\omega t)\) If a tuning fork for the note \(\mathrm{E}\) above middle \(\mathrm{C}\) on an even-tempered scale \(\left(\mathrm{E}_{4}\right)\) has a frequency of approximately 329.63 hertz (cycles per second), find \(\omega\). If the maximum displacement of the end of the tuning fork is 0.025 millimeter, Find a function that describes the movement of the tuning fork.

A perfect triangle is one having integers for sides for which the area is numerically equal to the perimeter. Show that the triangles with the given side lengths are perfect. (a) 9,10,17 (b) 6,25,29

Coast Guard Station Able is located 150 miles due south of Station Baker. A ship at sea sends an SOS call that is received by each station. The call to Station Able indicates the bearing of the ship is \(\mathrm{N} 55^{\circ} \mathrm{E} ;\) the call to Station Baker indicates the bearing of the ship is \(\mathrm{S} 60^{\circ} \mathrm{E}\). (a) How far is each station from the ship? (b) If a helicopter capable of flying 200 miles per hour is dispatched from the station nearest the ship, how long will it take to reach the ship?

According to Little League baseball official regulations, the diamond is a square 60 feet on a side. The pitching rubber is located 46 feet from home plate on a line joining home plate and second base (a) How far is it from the pitching rubber to first base? (b) How far is it from the pitching rubber to second base? (c) If a pitcher faces home plate, through what angle does he need to turn to face first base?

The Bermuda Triangle is roughly defined by Hamilton, Bermuda; San Juan, Puerto Rico; and Fort Lauderdale, Florida. The distances from Hamilton to Fort Lauderdale, Fort Lauderdale to San Juan, and San Juan to Hamilton are approximately \(1028,1046,\) and 965 miles, respectively. Ignoring the curvature of Earth, approximate the area of the Bermuda Triangle.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.