Chapter 8: Problem 113
If \(z=\tan \frac{\alpha}{2},\) show that \(\sin \alpha=\frac{2 z}{1+z^{2}}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 8: Problem 113
If \(z=\tan \frac{\alpha}{2},\) show that \(\sin \alpha=\frac{2 z}{1+z^{2}}\)
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Area of a Dodecagon Part I A regular dodecagon is a polygon with 12 sides of equal length. See the figure. (a) The area \(A\) of a regular dodecagon is given by the formula \(A=12 r^{2} \tan \frac{\pi}{12},\) where \(r\) is the apothem, which is a line segment from the center of the polygon that is perpendicular to a side. Find the exact area of a regular dodecagon whose apothem is 10 inches. (b) The area \(A\) of a regular dodecagon is also given by the formula \(A=3 a^{2} \cot \frac{\pi}{12},\) where \(a\) is the length of a side of the polygon. Find the exact area of a regular dodecagon if the length of a side is 15 centimeters.
Establish each identity. $$ \frac{\sin (\alpha+\beta)}{\cos \alpha \cos \beta}=\tan \alpha+\tan \beta $$
Discuss the following derivation: $$ \tan \left(\theta+\frac{\pi}{2}\right)=\frac{\tan \theta+\tan \frac{\pi}{2}}{1-\tan \theta \tan \frac{\pi}{2}}=\frac{\frac{\tan \theta}{\tan \frac{\pi}{2}}+1}{\frac{1}{\tan \frac{\pi}{2}}-\tan \theta}=\frac{0+1}{0-\tan \theta}=\frac{1}{-\tan \theta}=-\cot \theta $$ Can you justify each step?
Based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. Find the area of the sector of a circle of radius 6 meters formed by an angle of \(45^{\circ}\). Give both the exact area and an approximation rounded to two decimal places.
Establish each identity. $$ \cos (\alpha+\beta)+\cos (\alpha-\beta)=2 \cos \alpha \cos \beta $$
What do you think about this solution?
We value your feedback to improve our textbook solutions.