/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 113 If \(z=\tan \frac{\alpha}{2},\) ... [FREE SOLUTION] | 91Ó°ÊÓ

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If \(z=\tan \frac{\alpha}{2},\) show that \(\sin \alpha=\frac{2 z}{1+z^{2}}\)

Short Answer

Expert verified
\( \sin \alpha = \frac{2z}{1+z^2} \)

Step by step solution

01

Understand the given identity

The given expression involves trigonometric identities. We start with the given relation: \( z = \tan \frac{\alpha}{2} \). We need to show that \( \sin \alpha = \frac{2z}{1+z^2} \).
02

Use double-angle trigonometric identity

Recall the double-angle formula for sine: \( \sin \alpha = 2 \tan \frac{\alpha}{2} / (1 + \tan^2 \frac{\alpha}{2}) \). This can be written as \( \sin \alpha = \frac{2 \tan \frac{\alpha}{2}}{1 + \tan^2 \frac{\alpha}{2}} \).
03

Substitute \( z \) with \( \tan \frac{\alpha}{2} \)

We know from the given condition that \( z = \tan \frac{\alpha}{2} \). Substitute \( z \) in place of \( \tan \frac{\alpha}{2} \) in the identity. Therefore, \( \sin \alpha = \frac{2z}{1+z^2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Double-Angle Formula
In trigonometry, the double-angle formula is a crucial identity that relates the trigonometric functions of double angles to the functions of single angles. For sine, the double-angle formula is:
\[ \sin(2\theta) = 2 \sin(\theta) \cos(\theta) \]
However, it can also be expressed using tangent, which is especially useful in specific contexts, like the given problem. The version we use here is:
\[ \sin(\theta) = \frac{2 \tan(\frac{\theta}{2})}{1 + \tan^2(\frac{\theta}{2})} \]
Understanding this form is essential when the problem gives you a tangent instead of sine or cosine directly. You can convert the problem into simpler parts by using this powerful identity.
Tangent Half-Angle Identity
The tangent half-angle identity is a handy tool in trigonometry, especially when dealing with problems involving half-angles. The identity for the tangent of half an angle \( \frac{\alpha}{2} \) is given by:
\[ \tan \frac{\alpha}{2} = z \]
In our context, we use this identity to express other trigonometric functions in terms of \( z \). For sine, the formula evolves into:
\[ \sin(\alpha) = \frac{2z}{1 + z^2} \]
This transformation leverages the tangent half-angle to simplify the problem and reach a solution quicker. A good grasp of this identity not only helps in examinations but also builds a stronger understanding of trigonometric relationships.
Substitution Method
The substitution method is a mathematical technique used to simplify problems by replacing variables with their given values or expressions. In our problem, we use the substitution method to make the given trigonometric identities fit the form we need.
We start with the given condition: \( z = \tan \frac{\alpha}{2} \).
We then substitute \( z \) into the double-angle formula:
\[ \sin(\alpha) = \frac{2 \tan (\frac{\alpha}{2}) }{ 1 + \tan^2 (\frac{\alpha}{2}) } \]
Given \( z = \tan (\frac{\alpha}{2}) \), the formula becomes:
\[ \sin(\alpha) = \frac{2z}{1 + z^2} \]
Using substitution simplifies the problem by breaking it down into smaller, more manageable parts. This method is powerful for tackling complex equations and systems.

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Most popular questions from this chapter

Area of a Dodecagon Part I A regular dodecagon is a polygon with 12 sides of equal length. See the figure. (a) The area \(A\) of a regular dodecagon is given by the formula \(A=12 r^{2} \tan \frac{\pi}{12},\) where \(r\) is the apothem, which is a line segment from the center of the polygon that is perpendicular to a side. Find the exact area of a regular dodecagon whose apothem is 10 inches. (b) The area \(A\) of a regular dodecagon is also given by the formula \(A=3 a^{2} \cot \frac{\pi}{12},\) where \(a\) is the length of a side of the polygon. Find the exact area of a regular dodecagon if the length of a side is 15 centimeters.

Establish each identity. $$ \frac{\sin (\alpha+\beta)}{\cos \alpha \cos \beta}=\tan \alpha+\tan \beta $$

Discuss the following derivation: $$ \tan \left(\theta+\frac{\pi}{2}\right)=\frac{\tan \theta+\tan \frac{\pi}{2}}{1-\tan \theta \tan \frac{\pi}{2}}=\frac{\frac{\tan \theta}{\tan \frac{\pi}{2}}+1}{\frac{1}{\tan \frac{\pi}{2}}-\tan \theta}=\frac{0+1}{0-\tan \theta}=\frac{1}{-\tan \theta}=-\cot \theta $$ Can you justify each step?

Based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. Find the area of the sector of a circle of radius 6 meters formed by an angle of \(45^{\circ}\). Give both the exact area and an approximation rounded to two decimal places.

Establish each identity. $$ \cos (\alpha+\beta)+\cos (\alpha-\beta)=2 \cos \alpha \cos \beta $$

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