Chapter 8: Problem 114
Discuss the following derivation: $$ \tan \left(\theta+\frac{\pi}{2}\right)=\frac{\tan \theta+\tan \frac{\pi}{2}}{1-\tan \theta \tan \frac{\pi}{2}}=\frac{\frac{\tan \theta}{\tan \frac{\pi}{2}}+1}{\frac{1}{\tan \frac{\pi}{2}}-\tan \theta}=\frac{0+1}{0-\tan \theta}=\frac{1}{-\tan \theta}=-\cot \theta $$ Can you justify each step?
Short Answer
Step by step solution
Understand the angle addition formula for tangent
Apply the angle addition formula
Evaluate \(\tan(\frac{\pi}{2})\)
Rewrite the expression with \(\tan(\frac{\pi}{2})\)
Simplify the numerator
Simplify the denominator
Combine and conclude
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
trigonometric identities
- \(\text{sin}^2(x) + \text{cos}^2(x) = 1\)
- \(1 + \text{tan}^2(x) = \text{sec}^2(x)\)
- \(1 + \text{cot}^2(x) = \text{csc}^2(x)\)
- \(\text{sin}(\frac{\text{Ï€}}{2} - x) = \text{cos}(x)\)
- \(\text{cos}(\frac{\text{Ï€}}{2} - x) = \text{sin}(x)\)
- \(\text{tan}(\frac{\text{Ï€}}{2} - x) = \text{cot}(x)\)
angle addition formula
- \(\text{sin}(a + b) = \text{sin}(a)\text{cos}(b) + \text{cos}(a)\text{sin}(b)\)
- \(\text{cos}(a + b) = \text{cos}(a)\text{cos}(b) - \text{sin}(a)\text{sin}(b)\)
undefined tangent
- Consider \(\text{tan}(\frac{\pi}{2}) = \frac{1}{0}\) to highlight its undefined behavior.
- This redefinition helps in systematically simplifying the expression, ultimately allowing us to conclude \(\text{tan}(\theta + \frac{\pi}{2}) = -\text{cot}(\theta)\)