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Solve each system of equations.

x+z=72y−z=−3−x−3y+2z=11

Short Answer

Expert verified

The solution of the given equation x=−2,y=3is andz=9.

Step by step solution

01

– Use elimination method to make a system of two equations in two variables

x+z=72y−z=−3−x−3y+2z=11

....(1)....(2)....(3)

Adding (1) and (3), we get

x+z−7+−x−3y+2z−11=0x+z−7−x−3y+2z−11=03z−3y−18=03z−3y=183(z−y)=18z−y=6

....(4)

02

– Solve the system of two equations

Adding (2) and (4), we get

2y−z+3+z−y−6=02y−z+3+z−y−6=0y−3=0y=3

....(5)

Substituting in equation (4), we get

z−y=6z−3=6z=9

03

– Evaluate the value of x

Substituting the value of y and z in (1), we get

x+z=7x+9=7x=−2

Thus, the values are x=−2,y=3andz=9.

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