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Chapter 7: Q31. (page 351)

If $p (x) = 3 x^{2} - 2 x + 5 and r (x) = x^{3} + x + 1$ then find $4 p (a)$ .

Short Answer

Expert verified

The value of $4 p (a) = 12 a^{2} - 8 a + 20$ .

Step by step solution

01

Step 1. Write down the given information.

The given functions are $p (x) = 3 x^{2} - 2 x + 5 and r (x) = x^{3} + x + 1$ .

02

Step 2. Calculation.

Evaluating $4 p (a)$ by plugging $x = a$ in given function $p (x) = 3 x^{2} - 2 x + 5$ and multiply by 4.

$\begin{matrix} p (x) = 3 x^{2} 鈭� 2 x + 5.... (Given) \\ 4 p (x) = 4 (3 x^{2} 鈭� 2 x + 5) \\ 4 p (a) = 4 (3 {(a)}^{2} 鈭� 2 (a) + 5) \\ = 12 a^{2} 鈭� 8 a + 20 \end{matrix}$

03

Step 3. Conclusion.

The value of $4 p (a) = 12 a^{2} - 8 a + 20$ .

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