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Chapter 7: Q10. (page 350)

If $p (x) = 2 x^{3} + 6 x - 12 and q (x) = 5 x^{2} + 4$ then find $5 [q (2 a)]$ .

Short Answer

Expert verified

The value of $5 [q (2 a)] = 100 a^{2} + 20$ .

Step by step solution

01

Step 1. Write down the given information.

The given functions are $p (x) = 2 x^{3} + 6 x - 12 and q (x) = 5 x^{2} + 4$ .

02

Step 2. Calculation.

Evaluating $5 [q (2 a)]$ by plugging $x = 2 a$ in given function $q (x) = 5 x^{2} + 4$ and multiply by 5.

$\begin{matrix} q (x) = 5 x^{2} + 4.... (Given) \\ 5 [q (x)] = 5 [5 x^{2} + 4] \\ 5 [q (2 a)] = 5 [5 {(2 a)}^{2} + 4] \\ = 100 a^{2} + 20 \end{matrix}$

03

Step 3. Conclusion.

The value of $5 [q (2 a)] = 100 a^{2} + 20$ .

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Complete each of the following.

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