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If px=2x3+6x-12andqx=5x2+4 then find 3pa-qa+1.

Short Answer

Expert verified

The value of 3pa-qa+1=6a3-5a2+8a-45.

Step by step solution

01

Step 1. Write down the given information.

The given functions are px=2x3+6x-12andqx=5x2+4.

02

Step 2. Calculation.

Evaluating 3pa-qa+1 by plugging x=a in px=2x3+6x-12 and multiply by 3 and then subtract qa+1 by plugging x=a+1 in qx=5x2+4. Therefore,

role="math" localid="1648111658019" px=2x3+6x−12....Given3px=32x3+6x−123pa=32a3+6a−12=6a3+18a−36....1Now,qx=5x2+4qa+1=5a+12+4=5a2+10a+9....2

Subtract (2) from (1) gives,

3pa−qa+1=6a3+18a−36−5a2+10a+9=6a3−5a2+8a−45

03

Step 3. Conclusion.

The value of 3pa-qa+1=6a3-5a2+8a-45.

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