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Two sides of a parallelogram are contained in lines whose equations are 2.3x+1.2y=2.1and 4.1x-0.5y=14.3. Find the coordinates of a vertex of the parallelogram.

Short Answer

Expert verified

The required coordinates are 3,-4.

Step by step solution

01

Step 1- Determine the value of x

Use the provided equations and apply the Cramer’s rule for the value of x.

x=ebfdabcd

Substitute 2.3 in place of a, 4.1 in place of c, 1.2 in place of b, -0.5 in place of d, 2.1 in place of e and role="math" localid="1647245624304" 14.3 in place of f into role="math" localid="1647245617928" x=ebfdabcdand perform simplification of determinants to write the value of x.

x=2.11.214.3−0.52.31.24.1−0.5=2.1⋅−0.5−14.3⋅1.22.3⋅−0.5−4.1⋅1.2=−18.21−6.07=3

02

– Determine the value of y 

Apply the Cramer’s rule for the value of y.

y=aecfabcd

Substitute 2.3 in place of a, 4.1 in place of c, 1.2 in place of b, -0.5 in place of d, 2.1 in place of e and role="math" localid="1647245803291" 14.3 in place of f into role="math" localid="1647245798680" y=aecfabcdand perform simplification of determinants to write the value of y.

y=2.32.14.114.32.31.24.1−0.5=2.3⋅14.3−4.1⋅2.12.3⋅−0.5−4.1⋅1.2=24.28−6.07=−4

03

Step 3- Write the solution

The obtained value of x is 3 and y is -4 so the coordinates are 3,-4.

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