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Chapter 6: Q34. (page 291)

Determine whether each function has a maximum or minimum value. Then find the maximum or minimum value of the function.

f(x)=x2-8x+2

Short Answer

Expert verified

The function has minimum value that is -14.

Step by step solution

01

Step 1. Use the concept.

Consider the function f(x)=ax2+bx+c,a鈮�0, the x-coordinate of vertex is -b2a.

The graph of f(x)=ax2+bx+c,a鈮�0

  • opens up and has a minimum value when a>0, and
  • opens down and has a maximum value when a<0
02

Step 2. Given Information.

The given function is f(x)=x2-8x+2

03

Step 3. Solution.

In the functionf(x)=x2-8x+2, we have a=1,b=-8,c=2

Here, a=1>0

So, the graph opens up and has a minimum value.

The minimum value of the function is the y-coordinate of the vertex.

Thex-coordinate of the vertex is

鈭�b2a=鈭�鈭�82(1)..........a=1,b=鈭�8=4

Find they-coordinate of the vertex by evaluating the function for x=4.

f(4)=42-84+2=-14

So, the minimum value of function is -14.

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Most popular questions from this chapter

Solve each equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are located.

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