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In \(11-22,\) solve each triangle, that is, find the measures of the remaining three parts of the triangle to the nearest integer or the nearest degree. In \(\triangle A B C, a=22, b=18,\) and \(\mathrm{m} \angle C=130\)

Short Answer

Expert verified
c ≈ 34, A ≈ 23°, B ≈ 27°.

Step by step solution

01

Determine the Type of Triangle Problem

This problem involves solving a triangle given two sides and an included angle. Hence, this is an ASA (Angle-Side-Angle) problem.
02

Apply the Law of Cosines to Find Side c

Use the Law of Cosines to find the length of side \( c \):\[c^2 = a^2 + b^2 - 2ab \cdot \cos(C) \]Substitute \( a = 22 \), \( b = 18 \), and \( C = 130^\circ \):\[c^2 = 22^2 + 18^2 - 2 \cdot 22 \cdot 18 \cdot \cos(130^\circ) \]Calculate \( c^2 \) and then take the square root to find \( c \):\[c \approx 34 \] (rounded to the nearest integer).
03

Apply the Law of Sines to Find Angle A

Use the Law of Sines:\[\frac{a}{\sin(A)} = \frac{c}{\sin(C)}\]Substitute \( a = 22 \), \( c \approx 34 \), and \( C = 130^\circ \):\[\frac{22}{\sin(A)} = \frac{34}{\sin(130^\circ)}\]Solve for \( \sin(A) \), and then find \( A \) using the inverse sine function:\[A \approx 23^\circ \] (rounded to the nearest degree).
04

Find Angle B Using the Sum of Angles in a Triangle

Use the fact that the sum of angles in a triangle is 180 degrees:\[A + B + C = 180^\circ \]Substitute the known values: \( A \approx 23^\circ \) and \( C = 130^\circ \):\[23^\circ + B + 130^\circ = 180^\circ\]Solve for \( B \):\[B \approx 27^\circ \] (rounded to the nearest degree).
05

Compile the Triangle Solution

The triangle is solved with the following measurements:- Side \( c \approx 34 \)- Angle \( A \approx 23^\circ \)- Angle \( B \approx 27^\circ \)- Angle \( C = 130^\circ \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Law of Cosines
The Law of Cosines is a fundamental tool in trigonometry that helps to solve triangles, especially when you have two sides and an included angle. It's like a bridge between the sides and angles of a triangle, allowing us to connect and find missing information.

The formula is: \[c^2 = a^2 + b^2 - 2ab \cdot \cos(C)\]

We use it when we know two sides of a triangle and the angle between them (like in ASA problems). It's especially helpful for non-right triangles.

By substituting the known values, and solving for the unknown side, you can find its length. Then, by taking the square root, you get the exact measurement needed for further calculations. It’s a beautiful way to tackle problems in oblique triangles (triangles without a right angle).
ASA Triangle
An ASA triangle is a type of triangle where you know two angles and the side between them. It stands for "Angle-Side-Angle." Solving such triangles is a common task, especially in geometry and trigonometry.

In these triangles, you often use the Law of Sines or the Law of Cosines to find missing sides or angles. Given the two angles and the included side, ASA problems are straightforward and systematic.

Recognizing that you're dealing with an ASA triangle allows you to approach the problem with specific strategies, saving time and making the solving process more efficient. The steps involve calculating the third angle using the sum of angles in a triangle and then applying trigonometric laws to find remaining sides.
Triangle Solving
Triangle solving is a process of finding unknown sides and angles of a triangle. It's an essential skill in geometry and trigonometry. Each triangle has certain properties and using the right formulas is key to solving them.

The steps include:
  • Identify what type of triangle you are dealing with (ASA, SSS, etc.).
  • Use appropriate trigonometric laws and formulas, such as the Law of Sines or Cosines.
  • Find the missing sides and angles systematically.
  • Check your solution to ensure all triangle conditions (like sum of angles) are satisfied.

Practicing different types of triangle problems improves your problem-solving skills and helps in understanding broader mathematical concepts. Always verify your answers by cross-referencing with known triangle properties.
Sum of Angles in a Triangle
One of the most fundamental properties of triangles is that the sum of their interior angles is always 180 degrees. This fact is useful because, with just two known angles, you can easily find the third.

The equation for any triangle is: \[A + B + C = 180^\circ\]

This principle applies to all triangles, no matter their type (right, obtuse, or acute).

By using this in conjunction with other laws like Cosines or Sines, you can solve for unknown parts of the triangle. It's a simple yet powerful concept that acts as a check for the correctness of your triangle solutions.

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Most popular questions from this chapter

The length of one of the equal sides of an isosceles triangle measures 25.8 inches and each base angle measures 53 degrees. a. Find the measure of the base of the triangle to the nearest tenth. b. Find the perimeter of the triangle to the nearest inch.

A small park is in the shape of an isosceles trapezoid. The length of the longer of the parallel sides is 3.2 kilometers and the length of an adjacent side is 2.4 kilometers. A path from one corner of the park to an opposite corner is 3.6 kilometers long. a. Find, to the nearest tenth, the measure of each angle between adjacent sides of the park. b. Find, to the nearest tenth, the measure of each angle between the path and a side of the park. c. Find, to the nearest tenth, the length of the shorter of the parallel sides.

In \(3-14 :\) a. Determine the number of possible triangles for each set of given measures. b. Find the measures of the three angles of each possible triangle. Express approximate values to the nearest degree $$ b=12, c=10, \mathrm{m} \angle B=49 $$

Ross said that when he jogs, his path forms a triangle. Two sides of the triangle are 2.0 kilo- meters and 2.5 kilometers in length and the angle opposite the shorter side measures 45 degrees. Rosa said that when she jogs, her path also forms a triangle with two sides of length 2.0 kilometers and 2.5 kilometers and an angle of 45 degrees opposite the shorter side. Rosa said that her route is longer than the route Ross follows. Is this possible? Explain your answer.

In \(\triangle D E F, \mathrm{m} \angle D=56, \mathrm{m} \angle E=44,\) and \(d=37.5 .\) Find \(e\) to the nearest tenth.

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