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In \(3-14 :\) a. Determine the number of possible triangles for each set of given measures. b. Find the measures of the three angles of each possible triangle. Express approximate values to the nearest degree $$ b=12, c=10, \mathrm{m} \angle B=49 $$

Short Answer

Expert verified
One possible triangle with angles \(92^\circ, 49^\circ, 39^\circ\).

Step by step solution

01

Determine Triangle Type

We use the Law of Sines to explore whether a triangle can be formed and, if so, how many. Given that \( ext{m} \angle B = 49^\circ\), \(b = 12\), and \(c = 10\), we can use the Law of Sines: \(\frac{\sin B}{b} = \frac{\sin C}{c}\). We solve for \(\sin C\):\[\sin C = \frac{c \cdot \sin B}{b} = \frac{10 \cdot \sin 49^\circ}{12}\]Calculating this value will help us determine the possible angles of \(\angle C\).
02

Calculate \(\sin C\)

Compute \(\sin C\):\[\sin C = \frac{10 \cdot 0.7547}{12} \approx 0.629\]Since \(\sin C < 1\), there are possible triangle solutions. There might be one or two triangles depending on whether \(\angle C\) is acute or obtuse.
03

Calculate Possible Values of \(\angle C\)

Using \(\sin^{-1}\), calculate the possible values of \(\angle C\):\[\angle C \approx \sin^{-1}(0.629) \approx 39^\circ\]Since \(\sin \theta = \sin (180^\circ - \theta)\), the other possible angle for \(\angle C\) is:\[180^\circ - 39^\circ = 141^\circ\]Thus, \(\angle C\) can be either \(39^\circ\) or \(141^\circ\). We must determine if both can form a triangle with the given measures.
04

Evaluate Triangle Possibility

For \(\angle C = 39^\circ\):\[\angle A = 180^\circ - 49^\circ - 39^\circ = 92^\circ\]A triangle is possible with angles \(49^\circ, 39^\circ, 92^\circ\).For \(\angle C = 141^\circ\):\[\angle A = 180^\circ - 49^\circ - 141^\circ = -10^\circ\]A negative angle isn't feasible, confirming only one valid triangle.Therefore, only one triangle is possible for these measures.
05

Conclusion

The only possible triangle has angles approximately \(\angle A = 92^\circ\), \(\angle B = 49^\circ\), and \(\angle C = 39^\circ\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Triangle Congruence
When we talk about triangle congruence in the context of the Law of Sines, it's all about understanding whether the given sides and angles can form a triangle. To explore this, we must determine if a triangle can have one, two, or no possible arrangements for its angles and sides. In our exercise, we're given two sides, 12 and 10, and an angle, \(49^\circ\). By applying the Law of Sines, which states \(\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c}\), we assess the congruence potential by calculating the sine of the unknown angle, which helps us understand the triangle type.
  • If \(\sin C\) yields values that are less than 1 but positive, a triangle can be formed.
  • If \(\sin C\) yields a value greater than 1, no triangle is possible.
In our scenario, after computing, we found that only one triangle configuration is feasible. This is due to the fact that a second potential value for the angle would require a negative angle, which is not possible in a triangle.
Angle Calculation
Angle calculation is a crucial step in determining the potential number of triangles. We use trigonometric identities like \(\sin^{-1}\) to find the values of unknown angles. Once we determined \(\sin C\approx 0.629\), we calculated the possible angles \(\angle C\) could take:
  • The first possibility is \(\angle C \approx \sin^{-1}(0.629) \approx 39^\circ\).
  • The second possibility leverages the identity \(\sin \theta = \sin (180^\circ - \theta)\), giving us \(141^\circ\).
These values help us determine other angles using the fact that the sum of interior angles of a triangle is always \(180^\circ\). Using these calculations, we confirm that only one set of angles \(92^\circ, 49^\circ, \text{and } 39^\circ\) is valid, reaffirming the existence of only one triangle.
Trigonometric Functions
Trigonometric functions, like sine, cosine, and tangent, are vital for solving triangle problems. The Law of Sines is particularly essential when working with non-right triangles, as it relates the sides and angles in a proportional manner. In this exercise, we specifically used the sine function to find unknown angles from known side lengths and an angle.Understanding sine is crucial:
  • Sine describes the relationship between an angle in a triangle and the length of the opposite side, relative to the hypotenuse in a right triangle.
  • For a non-right triangle, like in our exercise, the Law of Sines uses sine to relate different sides and angles to solve for unknown measures.
The computation \(\sin C = \frac{10 \cdot \sin 49^\circ}{12}\) led us to a necessary angle value, showcasing how sine facilitates solving triangle-related queries. Through these principles, students can find missing angles or sides, provided they have adequate measurements from the other parts of the triangle.

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Most popular questions from this chapter

A small park is in the shape of an isosceles trapezoid. The length of the longer of the parallel sides is 3.2 kilometers and the length of an adjacent side is 2.4 kilometers. A path from one corner of the park to an opposite corner is 3.6 kilometers long. a. Find, to the nearest tenth, the measure of each angle between adjacent sides of the park. b. Find, to the nearest tenth, the measure of each angle between the path and a side of the park. c. Find, to the nearest tenth, the length of the shorter of the parallel sides.

Two points \(A\) and \(B\) are on the shoreline of Lake George. A surveyor is located at a third point \(C\) some distance from both points. The distance from \(A\) to \(C\) is 180.0 meters and the distance from \(B\) to \(C\) is 120.0 meters. The surveyor determines that the measure of \(\angle A C B\) is \(56.3^{\circ} .\) To the nearest tenth of a meter, what is the distance from \(A\) to \(B ?\)

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