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In \(3-10,\) find the exact values of \(\theta\) in the interval \(0^{\circ} \leq \theta \leq 360^{\circ}\) that make each equation true. $$ \cos 2 \theta+\sin ^{2} \theta=1 $$

Short Answer

Expert verified
\(\theta = 0^\circ, 180^\circ, 360^\circ \)

Step by step solution

01

Use Trigonometric Identity

Recall that the identity for cosine double angle is \( \cos 2\theta = 1 - 2\sin^2\theta \). Substitute this into the equation \( \cos 2\theta + \sin^2\theta = 1 \) to get \( 1 - 2\sin^2\theta + \sin^2\theta = 1 \).
02

Simplify the Equation

Combine like terms to simplify the equation: \( 1 - \sin^2\theta = 1 \). Then subtract 1 from both sides to get \( -\sin^2\theta = 0 \).
03

Solve for \(\sin\theta\)

The equation \( -\sin^2\theta = 0 \) simplifies to \( \sin^2\theta = 0 \). Taking the square root of both sides gives \( \sin\theta = 0 \).
04

Determine \(\theta\) Values

The solutions for \( \sin\theta = 0 \) within the interval \( 0^\circ \leq \theta \leq 360^\circ \) are \( \theta = 0^\circ, 180^\circ, 360^\circ \), because sine is zero at these angles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cosine Double Angle Identity
The cosine double angle identity is a useful trigonometric identity. It provides a relationship between the cosine of twice an angle and the sine of the angle. The formula for the cosine double angle is given by:
  • \( \cos 2\theta = \cos^2 \theta - \sin^2 \theta \)
  • Using Pythagorean identity: \( \sin^2 \theta + \cos^2 \theta = 1 \), the formula also transforms to \( \cos 2\theta = 1 - 2\sin^2 \theta \) and \( \cos 2\theta = 2\cos^2 \theta - 1 \)
These variations can be used interchangeably based on the context of the problem you are solving.
In the exercise provided, the formula \( \cos 2\theta = 1 - 2\sin^2 \theta \) is particularly useful, because it allows us to directly substitute and simplify the given equation \( \cos 2\theta + \sin^2 \theta = 1 \).
Substituting gives us \( 1 - 2\sin^2 \theta + \sin^2 \theta = 1 \). This step is the foundation for solving the equation and finding the angle \( \theta \).
Sine Function Zeros
The sine function has its zeros at specific angles where the value of sine is exactly zero. When solving trigonometric equations, particularly ones involving the sine function, identifying where sine is zero can instantly provide solutions.
The sine function, \( \sin \theta \), is zero at multiples of \( 180^\circ \), particularly:
  • \( \theta = 0^\circ \)
  • \( \theta = 180^\circ \)
  • \( \theta = 360^\circ \)
In the interval of \( 0^\circ \leq \theta \leq 360^\circ \), \( \sin\theta = 0 \) directly corresponds to these angle values.
In solving \( \cos 2\theta + \sin^2\theta = 1 \), we found through algebraic manipulation that \( \sin^2\theta = 0 \).
This leads to \( \sin \theta = 0 \), and the solutions are the zeros of the sine function within our specified interval, namely \( 0^\circ, 180^\circ, \text{and } 360^\circ \).
Solving Trigonometric Equations
Solving trigonometric equations involves using various identities and algebraic techniques to reveal angles that satisfy a given equation. The process usually involves:
  • Identifying and applying relevant trigonometric identities (like \( \cos 2\theta = 1 - 2\sin^2\theta \))
  • Simplifying the equation to make it more manageable
  • Solving for the trigonometric function values (like \( \sin \theta = 0 \))
  • Finding all angle solutions within the specified interval
In the example provided, the steps began with substituting the cosine double angle identity into \( \cos 2\theta + \sin^2\theta = 1 \).
This led us through simplifying and solving algebraically to find \( \sin^2\theta = 0 \).
Consequently, \( \sin \theta = 0 \) was determined, allowing us to identify the specific angles that solve the equation.
Each solution corresponds to a zero of the sine function within the interval, giving us the precise values \( 0^\circ, 180^\circ, \text{and } 360^\circ \).

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Most popular questions from this chapter

In \(9-14,\) find, to the nearest tenth of a degree, the values of \(\theta\) in the interval \(0^{\circ} \leq \theta<360^{\circ}\) that satisfy each equation. $$ \tan ^{2} \theta+4 \tan \theta-12=0 $$

In \(3-14,\) find the exact values of \(\theta\) in the interval \(0^{\circ} \leq \theta < 360^{\circ}\) that satisfy each equation. $$ \csc ^{2} \theta-\cot \theta-1=0 $$

Aaron solved the equation \(2 \sin \theta \cos \theta=\cos \theta\) by first dividing both sides of the equation by cos \(\theta\) . Aaron said that for \(0 \leq \theta \leq 2 \pi,\) the solution set is \(\left\\{\frac{\pi}{6}, \frac{5 \pi}{6}\right\\} .\) Do you agree with Aaron? Explain why or why not.

It is important to understand the underlying mathematics before using the calculator to solve trigonometric equations. For example, Adrian tried to use the intersect feature of his graphing calculator to find the solutions of the equation cot \(\theta=\sin \left(\theta-\frac{\pi}{2}\right)\) in the interval \(0 \leq \theta \leq \pi\) but got an error message. Follow the steps that Adrian used to solve the equation: (1) Enter \(Y_{1}=\frac{1}{\tan X}\) and \(Y_{2}=\sin \left(X-\frac{\pi}{2}\right)\) into the \(Y=\) menu. (2) Use the following viewing window to graph the equations: $$ X \min =0, \operatorname{Xmax}=\pi, X s c l=\frac{\pi}{6}, Y \min =-5, Y \max =5 $$ (3) The curves seem to intersect at \(\left(\frac{\pi}{2}, 0\right) .\) Press 2nd CALC 5 ENTER ENTER to select both curves. When the calculator asks for a guess, move the cursor near the intersection point using the arrow keys and then press ENTER a. Why does the calculator return an error message? b. Is \(\theta=\frac{\pi}{2}\) a solution to the equation? Explain.

In \(3-14,\) find the exact values of \(\theta\) in the interval \(0^{\circ} \leq \theta < 360^{\circ}\) that satisfy each equation. $$ 4 \cos ^{2} \theta+4 \sin \theta-5=0 $$

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