Chapter 5: Problem 43
Solve each equation. $$ 4 x^{2}+64=0 $$
Short Answer
Expert verified
The solutions are \(x = 4i\) and \(x = -4i\).
Step by step solution
01
Isolate the Quadratic Term
Start with the equation:\[ 4x^2 + 64 = 0 \]Subtract 64 from both sides to isolate the quadratic term:\[ 4x^2 = -64 \]
02
Simplify the Equation
Divide both sides of the equation by 4 to simplify:\[ x^2 = -16 \]
03
Solve for x by Taking the Square Root
Take the square root of both sides to solve for \(x\). Remember that taking the square root of a negative number results in an imaginary number:\[ x = \pm \sqrt{-16} \]
04
Simplify the Imaginary Number
Simplify the square root of the negative number using the imaginary unit \(i\), where \(i^2 = -1\):\[ x = \pm 4i \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
Quadratic equations are mathematical expressions that set a polynomial of degree two equal to zero. They are often written in the general form \(ax^2 + bx + c = 0\). Here, \(a\), \(b\), and \(c\) are constants, with \(a eq 0\). The simplest form of a quadratic equation is when \(b\) and \(c\) are zero, reducing it to \(ax^2 = 0\), although in practice you'll usually see all three terms present.
To solve a quadratic equation, you have several methods at your disposal. Some common techniques include:
To solve a quadratic equation, you have several methods at your disposal. Some common techniques include:
- Factoring the quadratic expression into two binomials and using the zero product property.
- Completing the square to transform the quadratic into a perfect square trinomial.
- Using the quadratic formula, \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), which provides the solutions directly.
Imaginary Numbers
Imaginary numbers arise when we take the square root of negative numbers, which does not result in a real number. Instead, mathematicians introduced the concept of imaginary numbers where \(i\) is defined such that \(i^2 = -1\).
When we solve quadratic equations with a negative discriminant, such as \(x^2 = -16\), the solutions are not real numbers but involve \(i\). For example, \(\sqrt{-16} = 4i\).
When we solve quadratic equations with a negative discriminant, such as \(x^2 = -16\), the solutions are not real numbers but involve \(i\). For example, \(\sqrt{-16} = 4i\).
- The imaginary unit \(i\) represents a rotational operation by 90 degrees in the complex plane.
- Imaginary numbers can be added, multiplied, and manipulated in conjunction with real numbers to form complex numbers, such as \(a + bi\), where \(a\) and \(b\) are real numbers.
Square Roots of Negative Numbers
Taking the square root of a negative number seemed impossible with just real numbers until the introduction of the imaginary unit \(i\). The square root of a negative number is expressed as a multiple of \(i\). For example, if we need to solve \(\sqrt{-16}\), we use the property of \(i\) to write the solution as \(4i\). This is because \((4i)^2 = 16i^2 = 16(-1) = -16\).
Here's how you can handle square roots of negative numbers in general:
Here's how you can handle square roots of negative numbers in general:
- Identify the negative number inside the square root, e.g., \(\sqrt{-n}\).
- Write it as \(\sqrt{n} \cdot \sqrt{-1}\).
- Replace \(\sqrt{-1}\) with \(i\), resulting in \(\sqrt{n}\cdot i\).