Chapter 5: Problem 43
Complete parts a-c for each quadratic function. a. Find the \(y\) -intercept, the equation of the axis of symmetry, and the \(x\) -coordinate of the vertex. b. Make a table of values that includes the vertex. c. Use this information to graph the function. $$ f(x)=\frac{1}{2} x^{2}+3 x+\frac{9}{2} $$
Short Answer
Step by step solution
Identify the Given Quadratic Function
Find the y-intercept
Find the Axis of Symmetry
Find the x-coordinate of the Vertex
Find the y-coordinate of the Vertex
Create a Table of Values
Graph the Quadratic Function
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Quadratic
- \
Axis of Symmetry
For our quadratic \( f(x) = \frac{1}{2}x^2 + 3x + \frac{9}{2} \), we use:
- \( a = \frac{1}{2} \)
- \( b = 3 \)
This axis is crucial when plotting the quadratic, as the vertex lies precisely on it, guiding the direction of the parabola's opening.
Y-intercept
For our quadratic function \( f(x) = \frac{1}{2}x^2 + 3x + \frac{9}{2} \), the \( y \)-intercept occurs when \( x = 0 \). Substituting \( x=0 \) into the equation:
- \( f(0) = \frac{1}{2}(0)^2 + 3(0) + \frac{9}{2} = \frac{9}{2} \).
Parabola
- The leading coefficient is \( \frac{1}{2} \), which is positive.
- The vertex, which can be the minimum or maximum point depending on the parabola's direction (here it is a minimum).
- The axis of symmetry, creating a mirror image from the vertex.
- Intersections with the axes, which help plot the function.
Table of Values
Given the function \( f(x) = \frac{1}{2}x^2 + 3x + \frac{9}{2} \), we create a table of values by choosing \( x \)-values around the vertex cord \( x = -3 \). By substituting these \( x \)-values into the function, we acquire various \( (x,f(x)) \) points:
- For \( x = -5 \), \( f(x) = \frac{19}{2} \).
- For \( x = -4 \), \( f(x) = 1 \).
- For \( x = -3 \), \( f(x) = 0 \).
- For \( x = -2 \), \( f(x) = \frac{5}{2} \).
- For \( x = -1 \), \( f(x) = 4 \).