Q21. Factor each polynomial.x2-10x+24... [FREE SOLUTION]

91影视

Algebra 1

Carter, Cuevas, Day, Holiday, Luchin

$Math Studyset 91影视 Explanations$ Math

Student Edition 路 801 pages

ISBN: 9780078884801

Chapter 8: Q21. (page 492)

Factor each polynomial.
$x^{2} - 10 x + 24$

Short Answer

Expert verified

The factors of the given polynomial are $(x 鈭� 4) (x 鈭� 6)$ .

Step by step solution

Step 1. Compare.

Compare a given trinomial to $a x^{2} + b x + c$ and write the values of $a, b$ and $c$ .

$a = 1 b = 鈭� 10 c = 24$

Step 2. List the factors.

List the factors of 24. Look for the pair of factors with a sum of $- 10$ .

Factors of 24	Sum of factors
1,24	25
2,12	14
$- 3, - 8$	$- 11$
$鈭� 4, 鈭� 6$	$鈭� 10$

Therefore, correct factors are $- 4$ and $- 6$ .

Step 3. Apply factoring pattern of ax2+bx+c.

There are two numbers having a product of 24 and some of $- 10$ . The numbers are $- 4$ and $- 6$ .

role="math" localid="1647521052429" $x^{2} 鈭� 10 x + 24 = (x + m) (x + p) = (x 鈭� 4) (x 鈭� 6)$

Therefore, the factors of $x^{2} 鈭� 10 x + 24$ are $(x 鈭� 4) (x 鈭� 6)$ .

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91影视

Factor each polynomial.
$x^{2} - 10 x + 24$

Short Answer

Step by step solution

Step 1. Compare.

Step 2. List the factors.

Step 3. Apply factoring pattern of ax2+bx+c.

One App. One Place for Learning.

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