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The Stanford University Heart Transplant Study was conducted to determine whether an experimental heart transplant program increased lifespan. Each patient entering the program was officially designated a heart transplant candidate, meaning that he was gravely ill and might benefit from a new heart. Patients were randomly assigned into treatment and control groups. Patients in the treatment group received a transplant, and those in the control group did not. The table below displays how many patients survived and died in each group. $$ \begin{array}{ccc} \hline & \text { control } & \text { treatment } \\ \hline \text { alive } & 4 & 24 \\ \text { dead } & 30 & 45 \\ \hline \end{array} $$ Suppose we are interested in estimating the difference in survival rate between the control and treatment groups using a confidence interval. Explain why we cannot construct such an interval using the normal approximation. What might go wrong if we constructed the confidence interval despite this problem?

Short Answer

Expert verified
Normal approximation can't be used due to small subgroup sizes in control. It risks inaccurate interval estimation.

Step by step solution

01

Understanding the Normal Approximation

The normal approximation is used to estimate the differences between two proportions when both samples are large enough. Generally, if both the number of successes and failures (alive and dead in this case) in each group are above 5, we can use the normal approximation to the binomial distribution.
02

Checking the Conditions for the Control Group

In the control group, there are 4 survivors (alive) and 30 non-survivors (dead). Since 4 < 5, the number of successes is less than 5, which does not satisfy the normal approximation condition.
03

Checking the Conditions for the Treatment Group

In the treatment group, 24 patients survived and 45 did not. Although both the number of alive and dead instances exceeds 5 here, for the confidence interval to be valid under normal approximation, it must also hold true for the control group, which it does not.
04

Evaluating the Implications of Using the Normal Approximation

If we proceeded with constructing the confidence interval using the normal approximation despite not meeting the necessary conditions, it could lead to inaccurate estimation of confidence bounds. This is because the standard error may be underestimated, increasing the chance of a Type I error (incorrectly rejecting a true null hypothesis).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a range of values, derived from sample data, that is likely to contain the true value of an unknown population parameter. Confidence intervals provide a way to estimate that population parameter, reflecting the degree of uncertainty around the sample estimate.

When calculating a confidence interval, you determine a range that you are confident contains the true parameter, often expressed as a percentage like 95% or 99%. This percentage is called the confidence level, and a 95% confidence level means you can be 95% certain the interval contains the true parameter.
  • For example, if you are estimating the difference in survival rates between two groups (such as those in a heart transplant study), you might calculate a confidence interval around this difference in survival rates.
  • The width of the confidence interval provides information about the precision of the estimate—narrower intervals indicate more precise estimates.
One key point to remember while constructing confidence intervals is to ensure that the underlying data satisfies necessary conditions for the statistical method chosen, otherwise, the interval may not accurately reflect the uncertainty around the estimate.
Normal Approximation
Normal approximation is a method used to simplify calculations when dealing with binomial distributions, especially when sample sizes are large. The idea is to approximate the binomial distribution with a normal distribution because the normal distributions are simpler to work with mathematically.

The normal approximation becomes valid under specific conditions. The rule of thumb is that both the number of "successes" and the number of "failures" (in this case, alive and dead patients) should each be at least 5. This ensures that the binomial distribution is sufficiently close to a normal distribution.
  • When these conditions are met, the normal distribution can then be used as an approximation to calculate probabilities and confidence intervals more easily.
  • If these conditions are not met, the approximation could yield misleading results.
Using the normal approximation where conditions are not met may lead to inaccurate confidence intervals and increased risk of statistical errors, such as Type I or Type II errors.
Binomial Distribution
The binomial distribution is a discrete probability distribution that models the number of successes in a fixed number of trials, where each trial has only two possible outcomes—success or failure. In the context of the heart transplant study, "alive" and "dead" can be considered as the two outcomes.

The distribution is defined by two parameters: the number of trials (n) and the probability of success in each trial (p). It answers questions such as "How many patients survive out of the total?" or "How often does a treatment result in survival?"
  • Calculating probabilities using the binomial distribution involves combinations (ways of arranging successes out of total trials) and individual success probabilities.
  • This type of distribution is particularly useful because it describes many natural phenomena in binary outcomes, providing a foundation for more complex statistical constructs, such as normal approximation.
Despite its usefulness, utilizing the binomial distribution directly can become unwieldy for large sample sizes, which is why approximations, like the normal approximation, are often employed—provided certain conditions are met.

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Most popular questions from this chapter

CA vs. OR, Part II. Exercise 6.22 provides data on sleep deprivation rates of Californians and Oregonians. The proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is \(8.0 \%\), while this proportion is \(8.8 \%\) for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. (a) Conduct a hypothesis test to determine if these data provide strong evidence the rate of sleep deprivation is different for the two states. (Reminder: Check conditions) (b) It is possible the conclusion of the test in part (a) is incorrect. If this is the case, what type of error was made?

A study asked 1,924 male and 3,666 female undergraduate college students their favorite color. A \(95 \%\) confidence interval for the difference between the proportions of males and females whose favorite color is black \(\left(p_{\text {male }}-p_{\text {female }}\right)\) was calculated to be (0.02,0.06) . Based on this information, determine if the following statements are true or false, and explain your reasoning for each statement you identify as false. \(^{28}\) (a) We are \(95 \%\) confident that the true proportion of males whose favorite color is black is \(2 \%\) lower to \(6 \%\) higher than the true proportion of females whose favorite color is black. (b) We are \(95 \%\) confident that the true proportion of males whose favorite color is black is \(2 \%\) to \(6 \%\) higher than the true proportion of females whose favorite color is black. (c) \(95 \%\) of random samples will produce \(95 \%\) confidence intervals that include the true difference between the population proportions of males and females whose favorite color is black. (d) We can conclude that there is a significant difference between the proportions of males and females whose favorite color is black and that the difference between the two sample proportions is too large to plausibly be due to chance. (e) The \(95 \%\) confidence interval for \(\left(p_{\text {female }}-p_{\text {male }}\right)\) cannot be calculated with only the information given in this exercise.

Exercise 6.11 presents the results of a poll evaluating support for a generically branded "National Health Plan" in the United States. \(79 \%\) of 347 Democrats and \(55 \%\) of 617 Independents support a National Health Plan. (a) Calculate a \(95 \%\) confidence interval for the difference between the proportion of Democrats and Independents who support a National Health Plan \(\left(p_{D}-p_{I}\right),\) and interpret it in this context. We have already checked conditions for you. (b) True or false: If we had picked a random Democrat and a random Independent at the time of this poll, it is more likely that the Democrat would support the National Health Plan than the Independent.

Greece has faced a severe economic crisis since the end of \(2009 .\) A Gallup poll surveyed 1,000 randomly sampled Greeks in 2011 and found that \(25 \%\) of them said they would rate their lives poorly enough to be considered "suffering". (a) Describe the population parameter of interest. What is the value of the point estimate of this parameter? (b) Check if the conditions required for constructing a confidence interval based on these data are met. (c) Construct a \(95 \%\) confidence interval for the proportion of Greeks who are "suffering". (d) Without doing any calculations, describe what would happen to the confidence interval if we decided to use a higher confidence level. (e) Without doing any calculations, describe what would happen to the confidence interval if we used a larger sample.

The General Social Survey asked a random sample of 1,390 Americans the following question: "On the whole, do you think it should or should not be the government's responsibility to promote equality between men and women?" \(82 \%\) of the respondents said it "should be". At a \(95 \%\) confidence level, this sample has \(2 \%\) margin of error. Based on this information, determine if the following statements are true or false, and explain your reasoning. \({ }^{15}\) (a) We are \(95 \%\) confident that between \(80 \%\) and \(84 \%\) of Americans in this sample think it's the government's responsibility to promote equality between men and women. (b) We are \(95 \%\) confident that between \(80 \%\) and \(84 \%\) of all Americans think it's the government's responsibility to promote equality between men and women. (c) If we considered many random samples of 1,390 Americans, and we calculated \(95 \%\) confidence intervals for each, \(95 \%\) of these intervals would include the true population proportion of Americans who think it's the government's responsibility to promote equality between men and women. (d) In order to decrease the margin of error to \(1 \%,\) we would need to quadruple (multiply by 4) the sample size. (e) Based on this confidence interval, there is sufficient evidence to conclude that a majority of Americans think it's the government's responsibility to promote equality between men and women.

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