Chapter 4: Problem 41
Distribution of \(\dot{p}\) : 1\. Suppose the true population proportion were \(p=0.5\) and a researcher takes a simple random sample of size \(n=50\). (a) Find and interpret the standard deviation of the sample proportion \(\dot{p}\). (b) Calculate the probability that the sample proportion will be larger than 0.55 for a random sample of size 50 .
Short Answer
Step by step solution
Standard Deviation Formula
Calculate \( \sigma_{\hat{p}} \) with Given Values
Interpret the Standard Deviation
Find the Z-Score for \( \hat{p} = 0.55 \)
Determine the Probability from the Z-Score
Final Answer
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sample Proportion
For example, in the given exercise, the researcher collects a sample of 50, and the sample proportion may vary due to random sampling. The sample proportion \( \hat{p} \) tells us what fraction of the individuals in the sample exhibit the characteristic of interest, calculated as \( \hat{p} = \frac{x}{n} \), where \( x \) is the number of successes observed in the sample, and \( n \) is the sample size.
- In practice, the value of \( \hat{p} \) helps researchers infer what they might expect to see in the entire population.
- It is the foundational basis for constructing confidence intervals and conducting hypothesis tests concerning population proportions.
Standard Deviation
For the sample proportion \( \hat{p} \), the standard deviation is calculated using the formula \( \sigma_{\hat{p}} = \sqrt{\frac{p(1-p)}{n}} \). In our exercise, with a population proportion \( p = 0.5 \) and a sample size \( n = 50 \), the standard deviation was found to be approximately 0.0707.
- This means if you were to take many samples of 50 individuals from the same population, the sample proportions would typically vary by about 0.0707 from the true population proportion.
- This concept is critical because a smaller standard deviation indicates that the sample proportion is a more reliable estimate of the population proportion.
Z-Score
To find the likelihood that the sample proportion is greater than a certain value, the z-score is calculated using the formula: \( z = \frac{\hat{p} - p}{\sigma_{\hat{p}}} \). In the exercise, we calculated the z-score when the sample proportion \( \hat{p} \) was 0.55, which resulted in a z-score of approximately 0.707.
- The z-score tells us how many standard deviations \( \hat{p} \) is from the mean \( p \).
- Understanding this helps in assessing whether a sample proportion is significantly different from the population proportion or if it could occur by random chance in a normal distribution.
Population Proportion
In research, determining or estimating this parameter is crucial for making inferences about the population as a whole. For the exercise, it is given that the population proportion \( p \) is 0.5. This value indicates that in reality, half of the population displays the characteristic of interest.
- While the population proportion provides the actual or theoretical specification for the population, sample statistics like the sample proportion offer estimates needed for practical analysis.
- Understanding the distinction between these two types of proportions is essential for accurate data interpretation and inference.