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Find all vectors \(\vec{v}\) in 2 dimensions having \(\|\vec{v}\|=13\) where the \(\tilde{i}\) -component of \(\vec{v}\) is \(5 \tilde{i}\) vectors: _________ (If you find more than one vector, enter them in a comma-separated list.)

Short Answer

Expert verified
vectors: \(\vec{v_1} = 5\tilde{i} + 12\tilde{j}\), \(\vec{v_2} = 5\tilde{i} - 12\tilde{j}\)

Step by step solution

01

Write the given information in mathematical form

Given that the magnitude of the vector, \(\|\vec{v}\|=13\), and the \(\tilde{i}\) component is \(5\tilde{i}\), we can represent the vector in the following format: \(\vec{v} = 5\tilde{i} + b\tilde{j}\)
02

Write the formula for the magnitude of a vector

To find the magnitude of a vector, we can use the formula: \(\|\vec{v}\| = \sqrt{a^2 + b^2}\) In our case, \(a=5\) and the magnitude of the vector is 13, so we can write the equation as: \(13 = \sqrt{5^2 + b^2}\)
03

Solve for the \(\tilde{j}\) component

Now, we need to solve for \(b\) to find the \(\tilde{j}\) component of the vector. First, we square both sides of the equation: \(13^2 = (5^2+b^2)\) \(169 = 25 + b^2\) Next, we subtract 25 from both sides: \(144 = b^2\) Now, we take the square root of both sides: \(b = \pm 12\)
04

Write down the vectors

Now that we have found the value(s) of \(b\), we can write down the vectors that satisfy the given conditions. We have two possibilities for \(b\), 12 and -12, which give us two distinct vectors: \(\vec{v_1} = 5\tilde{i} + 12\tilde{j}\) \(\vec{v_2} = 5\tilde{i} - 12\tilde{j}\) vectors: \(\vec{v_1} = 5\tilde{i} + 12\tilde{j}\), \(\vec{v_2} = 5\tilde{i} - 12\tilde{j}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

2-dimensional vectors
In mathematics and physics, vectors are used to represent quantities that have both magnitude and direction. A 2-dimensional vector lies in a plane and can be thought of as an arrow with a specific length and direction. These vectors are commonly represented in terms of their horizontal and vertical components, making them easy to visualize and work with.

A 2-dimensional vector is often denoted using letter notation, such as \( \vec{v} \), and can be expressed as a combination of the unit vectors \( \tilde{i} \) and \( \tilde{j} \). This shows how the vector moves horizontally (\( x \)-axis) and vertically (\( y \)-axis) respectively. For example, a vector \( \vec{v} = a\tilde{i} + b\tilde{j} \) indicates it moves \( a \) units along the horizontal direction and \( b \) units along the vertical direction.

Understanding 2-dimensional vectors is essential for solving problems involving motion, forces, and other vector-related concepts. It provides a simple yet powerful method of analyzing problems in physics, engineering, and beyond.
vector components
Vector components are fundamental in understanding vectors, as they describe how a vector can be broken down into its fundamental parts along the \( x \)-axis and \( y \)-axis. These components are essentially projections of the vector along each axis. For a vector \( \vec{v} = a\tilde{i} + b\tilde{j} \), \( a \) and \( b \) are the components of the vector.

The components make it easier to perform calculations, such as finding the vector's magnitude and performing operations like vector addition or subtraction. For example, knowing the \( \tilde{i} \)-component (horizontal) and the \( \tilde{j} \)-component (vertical), you can visualize the vector's direction and length.

When working with vectors, knowing how to manipulate and understand these components is crucial because they form the basis for calculating further vector properties, such as magnitude, as well as performing various vector operations that are common in scientific and engineering fields.
Pythagorean theorem
The Pythagorean theorem is a fundamental principle in mathematics that applies to right-angled triangles, and it plays a crucial role in understanding vectors. It allows us to find the vector magnitude by extending the theorem into the vector domain.

According to the Pythagorean theorem, for a right triangle with sides \( a \) and \( b \), and hypotenuse \( c \), the relationship is given by \( a^2 + b^2 = c^2 \). When we apply this to vectors, \( a \) and \( b \) become the vector's components (\( \tilde{i} \) and \( \tilde{j} \) components), and \( c \) becomes the vector's magnitude.

Thus, the magnitude of a vector \( \vec{v} = a\tilde{i} + b\tilde{j} \) can be found using the formula \( \|\vec{v}\| = \sqrt{a^2 + b^2} \). This relationship helps in solving a variety of vector problems, such as determining unknown components or confirming the length of a vector given its components. The use of the Pythagorean theorem in vector calculations simplifies and enhances our ability to solve real-world problems efficiently.

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Most popular questions from this chapter

Let \(\mathbf{u}=\langle 2,1\rangle\) and \(\mathbf{v}=\langle 1,2\rangle\). a. Determine the components and draw geometric representations of the vectors \(2 \mathbf{u}, \frac{1}{2} \mathbf{u},(-1) \mathbf{u},\) and (-3) \(\mathbf{u}\) on the same set of axes. b. Determine the components and draw geometric representations of the vectors \(\mathbf{u}+\mathbf{v}, \mathbf{u}+2 \mathbf{v},\) and \(\mathbf{u}+3 \mathbf{v}\) on the same set of axes. c. Determine the components and draw geometric representations of the vectors \(\mathbf{u}-\mathbf{v}, \mathbf{u}-2 \mathbf{v},\) and \(\mathbf{u}-3 \mathbf{v}\) on the same set of axes. d. Recall that \(\mathbf{u}-\mathbf{v}=\mathbf{u}+(-1) \mathbf{v}\). Sketch the vectors \(\mathbf{u}, \mathbf{v}, \mathbf{u}+\mathbf{v},\) and \(\mathbf{u}-\mathbf{v}\) on the same set of axes. Use the "tip to tail" perspective for vector addition to explain the geometric relationship between \(\mathbf{u}, \mathbf{v}\) and \(\mathbf{u}-\mathbf{v}\)

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