/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 A bungee jumper dives from a tow... [FREE SOLUTION] | 91Ó°ÊÓ

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A bungee jumper dives from a tower at time \(t=0\). Her height \(s\) in feet at time \(t\) in seconds is given by \(s(t)=100 \cos (0.75 t) \cdot e^{-0.2 t}+100\). a. Write an expression for the average velocity of the bungee jumper on the interval \([1,1+\) \(h]\) b. Use computing technology to estimate the value of the limit as \(h \rightarrow 0\) of the quantity you found in (a). c. What is the meaning of the value of the limit in (b)? What are its units?

Short Answer

Expert verified
The expression for average velocity is \(\frac{s(1 + h) - s(1)}{h}\). The estimated limit as \(h \rightarrow 0\) is the instantaneous velocity at \(t = 1\) second, with units of \(\text{ft/s}\).

Step by step solution

01

- Understand the given function

The height function of the bungee jumper is given by: \[ s(t) = 100 \cos (0.75 t) \cdot e^{-0.2 t} + 100 \] It represents her height in feet at time t in seconds.
02

- Write the expression for average velocity

The average velocity \(v\text{avg}\) on the interval \[1, 1 + h\] is given by: \[ v\text{avg} = \frac{s(1 + h) - s(1)}{h} \] To find this, we'll need to substitute into our height function.
03

- Calculate \(s(1)\)

First, we'll calculate the height at \(t=1\): \[ s(1) = 100 \cos (0.75 \cdot 1) \cdot e^{-0.2 \cdot 1} + 100 \] Compute this using a calculator to get a numerical value.
04

- Calculate \(s(1 + h)\)

Next, calculate the height at \(t=1+h\): \[ s(1+h) = 100 \cos (0.75 (1 + h)) \cdot e^{-0.2 (1 + h)} + 100 \] This is a bit more complex; simplify the expression as much as possible.
05

- Form the average velocity expression

Substitute \(s(1)\) and \(s(1+h)\) into the average velocity formula: \[ \frac{100 \cos (0.75 (1 + h)) \cdot e^{-0.2 (1 + h)} + 100 - (100 \cos (0.75 \cdot 1) \cdot e^{-0.2 \cdot 1} + 100)}{h} \]
06

- Simplify the average velocity expression

The expression simplifies to: \[ v\text{avg} = \frac{100 ( \cos (0.75 (1 + h)) \cdot e^{-0.2 (1 + h)} - \cos (0.75) \cdot e^{-0.2} )}{h} \]
07

- Estimate the limit as \(h \rightarrow 0\)

Using computing technology (a calculator or computer algebra system), estimate the limit of the expression as \(h \rightarrow 0\): \[ \lim_{{h \rightarrow 0}} \frac{s(1 + h) - s(1)}{h} \]
08

- Meaning and units of the limit

The limit represents the instantaneous velocity of the bungee jumper at \(t = 1\) second. The units of the instantaneous velocity are feet per second \(\text{ft/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Instantaneous Velocity
In this exercise, we are tasked with finding the average velocity of a bungee jumper and then determining its instantaneous velocity.
Instantaneous velocity is essentially the speed of an object at a single moment in time.
Mathematically, it is the limit of the average velocity as the time interval approaches zero.
The formula we use for average velocity on the interval \( [1, 1 + h] \) is: \[ v\text{{avg}} = \frac{{s(1 + h) - s(1)}}{h} \]
To find the instantaneous velocity, we calculate the limit of this expression as \( h \rightarrow 0 \).
This value tells us how fast the bungee jumper is moving at exactly \( t = 1 \) second. The process involves a limit calculation, which we will elaborate on below. It’s important to understand that instantaneous velocity gives a precise indication of the bungee jumper’s speed at a specific instant, unlike average velocity which is over a range.
Bungee Jumper Height Function
The height function provided in the exercise is critical for calculating both average and instantaneous velocities.
The height function is given as: \[ s(t) = 100 \cos(0.75 \cdot t) \cdot e^{-0.2 \cdot t} + 100 \]
This equation takes time \( t \) and calculates the height \( s \) in feet.
Elements of this function include:
  • The cosine function \( \cos(0.75 \cdot t) \) which models oscillation due to bungee jumping motions.
  • The exponential decay \( e^{-0.2 \cdot t} \) which represents the damping effect over time, reduction of bounce height.
  • The constant 100 added at the end, representing the initial height from which the jumper starts.
Understanding these elements helps see how the height changes over time, giving insights into the dynamics of a bungee jump.
Limit Calculation
To find the instantaneous velocity, we need to compute the limit of the average velocity expression as \( h \rightarrow 0 \).
This is a fundamental concept in calculus known as taking the derivative. Here’s how we approach it:
  • First, we calculate \( s(1) \) by substituting \( t = 1 \) in the height function: \[ s(1) = 100 \cos (0.75 \cdot 1) \cdot e^{-0.2 \cdot 1} + 100 \]
    Plugging this into a calculator provides a numerical result.
  • Next, calculate \( s(1 + h) \), which involves substituting \( t = 1 + h \) in the height function. Because it's more complicated, simplifying numerically via a calculator or a CAS tool helps.
  • Substitute these values into the average velocity formula: \[ \frac{100 \cos (0.75 (1 + h)) \cdot e^{-0.2 (1 + h)} + 100 - (100 \cos (0.75) \cdot e^{-0.2} + 100)}{h} \]
  • Simplify to: \[ v\text{avg} = \frac{100 \left ( \cos (0.75 (1 + h)) \cdot e^{-0.2 (1 + h)} - \cos (0.75) \cdot e^{-0.2} \right )}{h} \]
  • Estimate the limit using technology: \[ \lim_{{h \rightarrow 0}} \frac{s(1+h) - s(1)}{h} \] This limit is the instantaneous velocity at \( t = 1 \), commonly written in derivatives as \( s'(1) \).
  • The result is expressed in feet per second \((\text{{ft/s}})\).
This process, though technical, enables us to understand instantaneous changes in the height function, thus giving insights into velocity at a precise moment.

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Most popular questions from this chapter

A bungee jumper's height \(h\) (in feet) at time \(t\) (in seconds) is given in part by the table: $$ \begin{array}{llllllllllll} t & 0.0 & 0.5 & 1.0 & 1.5 & 2.0 & 2.5 & 3.0 & 3.5 & 4.0 & 4.5 & 5.0 \\ \hline h(t) & 200 & 184.2 & 159.9 & 131.9 & 104.7 & 81.8 & 65.5 & 56.8 & 55.5 & 60.4 & 69.8 \\ t & 5.5 & 6.0 & 6.5 & 7.0 & 7.5 & 8.0 & 8.5 & 9.0 & 9.5 & 10.0 \\ \hline h(t) & 81.6 & 93.7 & 104.4 & 112.6 & 117.7 & 119.4 & 118.2 & 114.8 & 110.0 & 104.7 \end{array} $$ a. Use the given data to estimate \(h^{\prime}(4.5), h^{\prime}(5),\) and \(h^{\prime}(5.5) .\) At which of these times is the bungee jumper rising most rapidly? b. Use the given data and your work in (a) to estimate \(h^{\prime \prime}(5)\). c. What physical property of the bungee jumper does the value of \(h^{\prime \prime}(5)\) measure? What are its units? d. Based on the data, on what approximate time intervals is the function \(y=h(t)\) concave down? What is happening to the velocity of the bungee jumper on these time intervals?

For each of the following prompts, sketch a graph on the provided axes of a function that has the stated properties. a. \(y=f(x)\) such that - \(f(-2)=2\) and \(\lim _{x \rightarrow-2} f(x)=1\) \- \(f(-1)=3\) and \(\lim _{x \rightarrow-1} f(x)=3\) \- \(f(1)\) is not defined and \(\lim _{x \rightarrow 1} f(x)=0\) \- \(f(2)=1\) and \(\lim _{x \rightarrow 2} f(x)\) does not exist. b. \(y=g(x)\) such that \- \(\text { - } g(-2)=3, g(-1)=-1, g(1)=-2, \text { and } g(2)=3\) \- At \(x=-2,-1,1\) and \(2, g\) has a limit, and its limit equals the value of the function at that point. \- \(g(0)\) is not defined and \(\lim _{x \rightarrow 0} g(x)\) does not exist.

According to the U.S. census, the population of the city of Grand Rapids, MI, was 181,843 in \(1980 ; 189,126\) in 1990 ; and 197,800 in 2000 . a. Between 1980 and 2000 , by how many people did the population of Grand Rapids grow? b. In an average year between 1980 and 2000 , by how many people did the population of Grand Rapids grow? c. Just like we can find the average velocity of a moving body by computing change in position over change in time, we can compute the average rate of change of any function \(f\). In particular, the average rate of change of a function \(f\) over an interval \([a, b]\) is the quotient $$\frac{f(b)-f(a)}{b-a}$$ What does the quantity \(\frac{f(b)-f(a)}{b-a}\) measure on the graph of \(y=f(x)\) over the interval \([a, b] ?\) d. Let \(P(t)\) represent the population of Grand Rapids at time \(t,\) where \(t\) is measured in years from January \(1,1980 .\) What is the average rate of change of \(P\) on the interval \(t=0\) to \(t=20 ?\) What are the units on this quantity? e. If we assume the population of Grand Rapids is growing at a rate of approximately \(4 \%\) per decade, we can model the population function with the formula $$P(t)=181843(1.04)^{t / 10}$$ Use this formula to compute the average rate of change of the population on the intervals \([5,10],[5,9],[5,8],[5,7],\) and [5,6] f. How fast do you think the population of Grand Rapids was changing on January 1 , 1985 ? Said differently, at what rate do you think people were being added to the population of Grand Rapids as of January \(1,1985 ?\) How many additional people should the city have expected in the following year? Why?

Consider the function \(g(x)=x^{2}-x+3\). a. Use the limit definition of the derivative to determine a formula for \(g^{\prime}(x)\). b. Use a graphing utility to plot both \(y=g(x)\) and your result for \(y=g^{\prime}(x) ;\) does your formula for \(g^{\prime}(x)\) generate the graph you expected? c. Use the limit definition of the derivative to find a formula for \(p^{\prime}(x)\) where \(p(x)=5 x^{2}-\) \(4 x+12\). d. Compare and contrast the formulas for \(g^{\prime}(x)\) and \(p^{\prime}(x)\) you have found. How do the constants \(5,4,12,\) and 3 affect the results?

Evaluate the limit $$\lim _{x \rightarrow-6} \frac{x^{2}-36}{x+6}$$ If the limit does not exist enter DNE. Limit =\(\square\)

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