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The temperature, \(H\), in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by \(H=f(t),\) where \(t\) is in minutes since the coffee was put on the counter. (a) Is \(f^{\prime}(t)\) positive or negative? [Choose: positive | negative] (Be sure that you are able to give a reason for your answer.) (b) What are the units of \(f^{\prime}(35)\) ?\(\square\) heln (units) Suppose that \(\left|f^{\prime}(35)\right|=1.2\) and \(f(35)=52 .\) Fill in the blanks (including units where needed) and select the appropriate terms to complete the following statement about the temperature of the coffee in this case. At \(\square\) minutes after the coffee was put on the counter, its [Choose: derivative | temperature change in temperature] is \(\square\) and will [Choose: increase | decrease] by about \(\square\) in the next 90 seconds.

Short Answer

Expert verified
At 35 minutes, the derivative is -1.2 degrees Celsius per minute. In the next 90 seconds, the temperature will decrease by 1.8 degrees Celsius.

Step by step solution

01

Determine if f'(t) is positive or negative

Since the coffee is initially hot and cools down over time, the temperature decreases. Thus, the rate of change of the temperature, represented by the derivative \( f'(t) \), is negative.
02

Find the units of f'(35)

The function \( f(t) \) gives the temperature in degrees Celsius, and \( t \) is in minutes. Hence, the derivative \( f'(t) \) represents the rate of change of temperature with respect to time. Therefore, the units of \( f'(35) \) are \( \text{degrees Celsius per minute} \).
03

Interpret given values and complete the statement

We are given \( |f'(35)| = 1.2 \) and \( f(35) = 52 \). Since \( f'(35) \) is the rate of change of temperature at 35 minutes, it means the temperature is changing at a rate of 1.2 degrees Celsius per minute. The given statement is: 'At \(\boxed{a}\) minutes after the coffee was put on the counter, its [derivative | temperature change in temperature] is \( \boxed{b} \) and will [increase | decrease] by about \( \boxed{c} \) in the next 90 seconds.' Filling in the blanks: 'A 35 minutes after the coffee was put on the counter, its derivative is 1.2 degrees Celsius per minute and it will decrease by about 1.8 degrees Celsius in the next 90 seconds' (since 90 seconds equals 1.5 minutes, multiply the rate 1.2 degrees Celsius per minute by 1.5).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

derivatives
Derivatives are one of the fundamental concepts in calculus. They measure how a function changes as its input changes. More formally, the derivative of a function at a particular input is the slope of the tangent line to the function's graph at that point.

For example, if you have a function that describes the temperature of a cup of coffee over time, the derivative of this function will tell you how quickly the temperature is changing at any given moment.

You can think of the derivative as the 'instantaneous rate of change'—how fast something is changing right now, as opposed to an average rate of change over a longer period. This is particularly useful in problems where we need to predict future behaviors based on current trends.

In mathematical notation, if you have a function \( f(t) \), then its derivative is written as \( f'(t) \) or \( \frac{df}{dt} \). In our coffee temperature example, \( f'(t) \) represents how quickly the coffee is cooling down at time \( t \).
rate of change
The rate of change is a measure of how one quantity changes in relation to another quantity. In our coffee temperature example, the rate of change tells us how the temperature of the coffee changes over time.

The derivative, \( f'(t) \), gives us a precise way to find this rate. If \( f(t) \) measures temperature in degrees Celsius as the function of time in minutes, then \( f'(t) \) gives the rate of temperature change in degrees Celsius per minute.

In the exercise, we found that \( f'(35) = -1.2 \). This means that 35 minutes after the coffee was placed on the counter, the temperature decreases at a rate of 1.2 degrees Celsius per minute. A negative rate of change indicates that the temperature is going down.

Understanding the rate of change is useful in many real-world applications like physics, engineering, and economics. It helps us predict how quickly things like temperatures, speeds, or prices will change over time.
temperature function
A temperature function describes how temperature changes over time or another variable. In our coffee problem, \( H = f(t) \) represents the temperature of the coffee as a function of time.

The function \( f(t) \) might look something like a smooth curve that starts high (when the coffee is hot) and gradually slopes downward as the coffee cools.

Through the derivative \( f'(t) \), we can understand more about how the temperature changes at specific points in time. Knowing that \( |f'(35)| = 1.2 \) helps us quantify that, exactly 35 minutes after the coffee was placed on the counter, it is cooling at a rate of 1.2 degrees Celsius per minute.

Additionally, projecting this rate over a short time interval (like 90 seconds) can help us estimate how much the temperature will drop in the near future. This way, we quickly see that in 90 seconds or 1.5 minutes, the coffee will decrease by roughly 1.8 degrees Celsius.

Such temperature functions can be applied not just to cooling coffee but also to warming engines, cooling electronics, and even the human body. They provide a mathematical way to model and predict thermal behaviors.

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Most popular questions from this chapter

The displacement (in meters) of a particle moving in a straight line is given by $$s=t^{2}-5 t+12$$ where \(t\) is measured in seconds. (A) (i) Find the average velocity over the time interval [3,4] . Average Velocity \(=\square\) (ii) Find the average velocity over the time interval [3.5,4]. Average Velocity \(=\square\) (iii) Find the average velocity over the time interval [4,5] . Average Velocity \(=\square\) (iv) Find the average velocity over the time interval [4,4.5] . Average Velocity \(=\square\) (B) Find the instantaneous velocity when \(t=4\) \(=\square\) Instantaneous velocity \(=\square\)

The temperature, \(H\), in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by \(H=f(t),\) where \(t\) is in minutes since the coffee was put on the counter. (a) Is \(f^{\prime}(t)\) positive or negative? [Choose: positive | negative] (b) What are the units of \(f^{\prime}(25) ?\) \(\square\) Suppose that \(\left|f^{\prime}(25)\right|=0.6\) and \(f(25)=65 .\) Fill in the blanks (including units where needed) and select the appropriate terms to complete the following statement about the temperature of the coffee in this case. At \(\square\) minutes after the coffee was put on the counter, its [Choose: derivative | temperature | change in temperature] is \(\square\) and will [Choose: increase | decrease] by about \(\square\) in the next 60 seconds.

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