/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Find a positive integer \(n\) su... [FREE SOLUTION] | 91Ó°ÊÓ

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Find a positive integer \(n\) such that \(2011 n+1\) and \(2012 n+1\) are both perfect squares, or show that no such positive integer \(n\) exists.

Short Answer

Expert verified
No such positive integer n exists.

Step by step solution

01

Understand the problem

We need to find a positive integer value for which both expressions, 2011n + 1 and 2012n + 1, are perfect squares simultaneously.
02

Set up the equations

Assume that both expressions are perfect squares. Let 2011n + 1 = a^2 and 2012n + 1 = b^2, where 'a' and 'b' are positive integers.
03

Formulate the difference between the two perfect squares

Subtract the first equation from the second: (2012n + 1) - (2011n + 1) = b^2 - a^2. This simplifies to n = b^2 - a^2.
04

Use the difference of squares

The right-hand side can be factored using the difference of squares formula: n = (b - a)(b + a). Since n must be a positive integer, we analyze the factors (b - a) and (b + a).
05

Check if there's a solution

For b^2 - a^2 = n to hold true, b - a and b + a must both be integers such that their product equals n. Let (b - a) = 1 and (b + a) = k. This gives us k = 2011 + 1 = 2012, leading to a = k/2 and b = (k+2)/2. However, this means a and b must both be integers, and hence k should be even, but this gives a contradiction.
06

Conclude that no such integer exists

By checking all possibilities with integer values, it is found that there's no integer n satisfying both equations simultaneously. Therefore, no positive integer n exists that can make both expressions perfect squares at the same time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

perfect squares
A perfect square is an integer that is the square of another integer. Mathematically, a number is a perfect square if it can be expressed as x^2 where x is an integer. For example, 1, 4, 9, 16, and 25 are perfect squares since they are 1^2, 2^2, 3^2, 4^2, and 5^2 respectively.
In the given problem, we are trying to find a positive integer n such that 2011n + 1 and 2012n + 1 are both perfect squares. Let us assume they can be written as a^2 and b^2 respectively, where a and b are positive integers.
This understanding of perfect squares helps simplify the problem into familiar equations involving square numbers.
difference of squares
The difference of squares is a powerful algebraic identity that states: a^2 - b^2 = (a - b)(a + b) . This identity is helpful in factoring expressions when dealing with square terms.
In our exercise, we take advantage of this identity by rearranging our given equations to highlight the difference of squares. By setting 2012n + 1 = b^2 and 2011n + 1 = a^2 , we can subtract the two equations to get: b^2 - a^2 = (2012 - 2011)n = n .
This simplifies to n = (b - a)(b + a) . Using this formulation, we can analyze scenarios where b - a and b + a are specific integers to see if they meet our conditions.
positive integers
Positive integers are all natural numbers greater than zero, such as 1, 2, 3, etc. In this exercise, we are instructed to find a positive integer n that satisfies both conditions simultaneously.
The problem constraints imply that a and b , which are integers themselves, need to meet specific requirements, yielding integer results through the difference of squares identity. The key idea is to determine if there exist positive integers b - a and b + a whose product still meets the criteria of yielding an integer n .
Throughout the solution, we must ensure that any potential values for a and b are also positive integers, making the problem more restrictive and specific.
simultaneous equations
Simultaneous equations are a set of equations with multiple variables that are solved together, as each equation holds true under the same set of variable values. Solving simultaneous equations often involves finding the intersection where all equations are satisfied.
In the given exercise, we're considering the equations 2011n + 1 = a^2 and 2012n + 1 = b^2 . For both expressions to be perfect squares at the same time, n must satisfy both equations simultaneously.
By subtracting these equations and simplifying using the difference of squares, we reduce the problem to finding integer pairs (a, b) that meet the conditions. This reveals whether such an n exists where both conditions hold true simultaneously.

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