Chapter 6: Problem 82
Assume that \(f(x)=a^{x}\), where \(a>1\). Work these exercises in order. If \(f\) has an inverse function \(f^{-1},\) sketch \(f\) and \(f^{-1}\) on the same axes.
Short Answer
Expert verified
Draw both \(f(x) = a^x\) and \(f^{-1}(x) = \log_a(x)\), ensuring they reflect across \(y = x\).
Step by step solution
01
Understand the function
The given function is an exponential function, \(f(x) = a^x\), where \(a > 1\). Exponential functions are one-to-one, so they have inverse functions.
02
Find the inverse function
To find the inverse \(f^{-1}(x)\), set \(y = a^x\) and solve for \(x\) in terms of \(y\). Start with \(y = a^x\), take the logarithm base \(a\) of both sides to get \(\log_a(y) = x\). Thus, the inverse function is \(f^{-1}(x) = \log_a(x)\).
03
Key Characteristics of \(f(x) = a^x\)
The graph of \(f(x) = a^x\) passes through the point (0,1) and increases rapidly. It has a horizontal asymptote on the x-axis at \(y=0\).
04
Key Characteristics of \(f^{-1}(x) = \log_a(x)\)
The graph of \(f^{-1}(x) = \log_a(x)\) passes through the point (1,0) and increases slowly. It has a vertical asymptote at \(x=0\).
05
Sketching \(f(x) = a^x\)
First, draw the curve for \(f(x) = a^x\) ensuring it passes through (0,1) and increases without bound as \(x\) increases. Show the horizontal asymptote at \(y=0\).
06
Sketching \(f^{-1}(x) = \log_a(x)\)
On the same axes, draw the curve for \(f^{-1}(x) = \log_a(x)\). Ensure it passes through (1,0) and increases as \(x\) increases. Show the vertical asymptote at \(x=0\).
07
Reflect across \(y=x\)
Check that \(f(x)\) and \(f^{-1}(x)\) are reflections across the line \(y = x\). This confirms that they are inverses of each other.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Functions
An exponential function is a mathematical function of the form \( f(x) = a^x \), where \( a \) is a positive real number greater than 1. These functions are powerful because they grow (or decay) at rates proportional to their current value. This means as \( x \) increases, the function values increase rapidly. The graph of an exponential function goes through the point (0,1) because any number raised to the power of 0 is 1. For \( a > 1 \), the function will always increase as \( x \) increases, producing a curve that gets steeper and steeper. An important feature of exponents is that they have a horizontal asymptote, meaning the graph approaches the x-axis but never actually touches it. This is visible at \( y=0 \) in the graph of exponential functions. Remember: exponential functions are one-to-one, meaning they never have the same output value for two different input values, which is why they have inverse functions.
Logarithmic Functions
Logarithmic functions are the inverses of exponential functions; if \( f(x) = a^x \), then \( f^{-1}(x) = \log_a(x) \). This means the logarithm function answers the question: "To what power must \( a \) be raised, to get \( x \)?" For example, if \( a = 10 \), a logarithm tells you which power to raise 10 to get a certain number. A few key characteristics of logarithms include:
- They go through the point (1,0) because the logarithm of 1 in any base is always 0.
- They increase, but much more slowly than exponential functions.
- There is a vertical asymptote at \( x=0 \), meaning the graph cannot go past \( x=0 \) and instead drops down infinitely near this axis.
Graph Sketching
Graph sketching is a vital skill in mathematics that involves plotting a function to visualize how it behaves. To effectively sketch both an exponential function and its inverse logarithmic function:
- Start by plotting the exponential function \( f(x) = a^x \). Since \( a > 1 \), it will rise sharply as \( x \) increases, crossing the point (0,1).
- Mark the horizontal asymptote at \( y = 0 \), indicating that the curve won't touch the x-axis.
- Next, draw the logarithmic function \( f^{-1}(x) = \log_a(x) \). It will pass through the point (1,0) and show a slow, steady increase.
- Indicate the vertical asymptote at \( x = 0 \), since the log function cannot take a zero or negative input.