Chapter 6: Problem 95
Use the change-of-base rule to find an approximation for each logarithm. $$\log _{29} 7.5$$
Short Answer
Expert verified
\( \log_{29} 7.5 \approx 0.5983 \).
Step by step solution
01
Understand the Change-of-Base Formula
The change-of-base formula allows us to convert a logarithm in any base to a different base, typically base 10 or base e, which are easier to compute. The formula is:\[\log_b a = \frac{\log_c a}{\log_c b}\]where \(c\) is the new base we are converting to, commonly 10 or e (natural logarithm).
02
Apply the Change-of-Base Formula
In this problem, we want to find \( \log_{29} 7.5 \). Using the change-of-base formula, we can convert it to:\[\log_{29} 7.5 = \frac{\log_{10} 7.5}{\log_{10} 29}\]Here, we chose base 10 (common logarithm) for simplicity, as it can be easily calculated using a calculator.
03
Calculate Individual Logarithms
Now, we calculate the logarithms using base 10:1. \( \log_{10} 7.5 \) is approximately 0.8751.2. \( \log_{10} 29 \) is approximately 1.4624.
04
Compute the Quotient
Now we plug these values back into the change-of-base formula:\[\log_{29} 7.5 = \frac{0.8751}{1.4624} \]Calculate the division to get the result.
05
Final Calculation and Approximation
Performing the division \( \frac{0.8751}{1.4624} \) gives approximately 0.5983. Therefore, \( \log_{29} 7.5 \approx 0.5983 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Logarithms
Logarithms are a mathematical concept used to describe the power or exponent that a base number must be raised to in order to obtain a given value. For example, in the logarithmic expression \( \log_b a \), \( b \) is the base, and the expression states "the power to which \( b \) must be raised to produce \( a \)."
Logarithms are the inverse of exponentiation. If \( b^c = a \), then \( \log_b a = c \). This inverse relationship makes logarithms particularly useful for simplifying expressions and solving equations that involve exponential growth or decay.
There are several types of logarithms based on the base used:
Logarithms are the inverse of exponentiation. If \( b^c = a \), then \( \log_b a = c \). This inverse relationship makes logarithms particularly useful for simplifying expressions and solving equations that involve exponential growth or decay.
There are several types of logarithms based on the base used:
- Common logarithms (base 10) are represented as \( \log_{10} \).
- Natural logarithms (base \( e \), where \( e \approx 2.718 \)) are represented as \( \ln \).
- Binary logarithms (base 2) are useful in computer science.
Base Conversion
Base conversion is the process of changing a logarithm from one base to another. This is especially useful when dealing with logarithms of uncommon bases, which are not directly supported by most calculators.
The change-of-base formula is a powerful tool for this: \( \log_b a = \frac{\log_c a}{\log_c b} \). Here, you convert the original base \( b \) logarithm into an equivalent expression using a new base, \( c \). This allows evaluation using simpler, more-accessible bases like 10 or \( e \).
In practical terms, to convert \( \log_{29} 7.5 \) using base 10:
The change-of-base formula is a powerful tool for this: \( \log_b a = \frac{\log_c a}{\log_c b} \). Here, you convert the original base \( b \) logarithm into an equivalent expression using a new base, \( c \). This allows evaluation using simpler, more-accessible bases like 10 or \( e \).
In practical terms, to convert \( \log_{29} 7.5 \) using base 10:
- Compute \( \log_{10} 7.5 \).
- Compute \( \log_{10} 29 \).
- Divide these values: \( \frac{\log_{10} 7.5}{\log_{10} 29} \).
Mathematical Approximation
Mathematical approximation is crucial when working with values that aren't neat whole numbers or cannot be precisely calculated. Approximations allow for practical solutions in real-world applications where exact values are not necessary or possible.
In the context of logarithms, we often deal with irrational numbers that have non-terminating decimal expansions. Calculators typically provide decimal approximations for these, such as 0.8751 for \( \log_{10} 7.5 \) and 1.4624 for \( \log_{10} 29 \).
Though these approximations are not exact, they are sufficiently accurate for most purposes, ensuring that mathematical problems remain solvable without unnecessary complexity:
In the context of logarithms, we often deal with irrational numbers that have non-terminating decimal expansions. Calculators typically provide decimal approximations for these, such as 0.8751 for \( \log_{10} 7.5 \) and 1.4624 for \( \log_{10} 29 \).
Though these approximations are not exact, they are sufficiently accurate for most purposes, ensuring that mathematical problems remain solvable without unnecessary complexity:
- Provides quick, practical solutions where exactitude isn't essential.
- Helps in simplifying complex mathematical expressions.
- Facilitates understanding and calculation of real-world problems.