Chapter 3: Problem 55
Solve each equation. For equations with real solutions, support your answers graphically. $$4 x^{2}-20 x+25=0$$
Short Answer
Expert verified
The equation has one real solution: \(x = 2.5\).
Step by step solution
01
Identify the Type of Equation
The given equation is a quadratic equation in the form of \(ax^2 + bx + c = 0\). Here, we have \(a = 4\), \(b = -20\), and \(c = 25\).
02
Calculate the Discriminant
The discriminant \(D\) of a quadratic equation \(ax^2 + bx + c = 0\) can be found using the formula \(D = b^2 - 4ac\). Substitute the values: \(D = (-20)^2 - 4(4)(25) = 400 - 400 = 0\).
03
Analyze the Discriminant
Since the discriminant \(D = 0\), the quadratic equation has a repeated real root. This means there is exactly one real solution.
04
Use the Quadratic Formula
The solution for \(x\) can be found using the quadratic formula: \(x = \frac{-b \pm \sqrt{D}}{2a}\). Substituting \(b = -20\), \(D = 0\), and \(a = 4\), we get: \(x = \frac{-(-20) \pm \sqrt{0}}{2(4)} = \frac{20}{8} = 2.5\).
05
Graphical Interpretation
The quadratic function \(4x^2 - 20x + 25\) can be graphed as a parabola. Since the solution \(x = 2.5\) is a repeated root, the vertex of the parabola touches the x-axis at this point, indicating the root is \(x = 2.5\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant in Quadratic Equations
The discriminant is a crucial part of quadratic equations. It helps determine the nature and number of roots of the equation. For a quadratic equation of the form \( ax^2 + bx + c = 0 \), the discriminant \( D \) is calculated with the formula: \[ D = b^2 - 4ac \] The value of \( D \) tells us how many real solutions the equation has:
- If \( D > 0 \), there are two distinct real solutions.
- If \( D = 0 \), there's exactly one real solution, called a repeated or double root.
- If \( D < 0 \), no real solutions exist, implying complex solutions.
Real Solutions and Their Calculation
Real solutions of a quadratic equation are the x-values that satisfy the equation. After determining the discriminant, the real solutions can be found using the quadratic formula: \[ x = \frac{-b \pm \sqrt{D}}{2a} \] With \( D = 0 \), the formula simplifies as the \( \pm \) component vanishes, giving just one solution. For our equation \( 4x^2 - 20x + 25 = 0 \), we substituted \( b = -20 \), \( D = 0 \), and \( a = 4 \) into the formula, resulting in \( x = \frac{20}{8} = 2.5 \). Therefore, the quadratic equation has one real solution at \( x = 2.5 \). Understanding real solutions helps students grasp the concept of roots in quadratic equations, particularly in how they relate to the equation's graph.
Graphical Interpretation of Quadratic Equations
Graphically interpreting a quadratic equation involves graphing the related function and observing its intersection with the x-axis. The equation \( ax^2 + bx + c = 0 \) forms a parabola when graphed. How the parabola interacts with the x-axis tells us about the solutions.
- If the parabola intersects the x-axis at two points, the equation has two real solutions.
- If it touches the x-axis at a single point, there is one real solution, a situation known as a "repeated root" or "vertex touching the axis" phenomenon.
- If it does not intersect the x-axis, the equation has no real solutions but complex ones instead.