Chapter 3: Problem 55
Find the equation of the quadratic function satisfying the given conditions. (Hint: Determine values of \(a\), \(h,\) and \(k\) that satisfy \(P(x)=a(x-h)^{2}+k .\) ) Express your answer in the form \(P(x)=a x^{2}+b x+c\). Use your calculator to support your results. Vertex \((-1,-4) ;\) through \((5,104)\)
Short Answer
Step by step solution
Identify the Vertex
Substitute Vertex in Vertex Form
Substitute Known Point to Find 'a'
Substitute 'a' into Vertex Form
Expand to Standard Form
Verify the Solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Vertex Form
Transitioning to Standard Form
For instance, given the vertex form \(P(x) = 3(x + 1)^2 - 4\), first expand \((x + 1)^2\) to get \(x^2 + 2x + 1\). Next, distribute the \(3\), resulting in:
- \(3(x^2 + 2x + 1) = 3x^2 + 6x + 3\)
- \(3x^2 + 6x + 3 - 4 = 3x^2 + 6x - 1\)
Equation Solving Techniques
Let's say we have \(P(x) = 3x^2 + 6x - 1\). To solve using the quadratic formula, identify \(a = 3\), \(b = 6\), and \(c = -1\). Substitute these into the formula to find the solutions for \(x\). The discriminant \(b^2 - 4ac\) tells us about the nature of the roots:
- A positive discriminant implies two real and distinct roots.
- Zero indicates one real, repeated root.
- Negative means two complex roots.
Finding the Vertex
Suppose \(P(x) = 3x^2 + 6x - 1\), calculate \(h\):
- \(h = \frac{-6}{2*3} = -1\)
- \(k = 3(-1)^2 + 6(-1) - 1 = -4\)