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A total ofmitems are to be sequentially distributed among ncells, with each item independently being put in a cell jwith probability role="math" localid="1647437056272" pj,j=1,...,n. Find the expected number of collisions that occur, where a collision occurs whenever an item is put into a non-empty cell.

Short Answer

Expert verified

The expected number of collisions that occur, where a collision occurs whenever an item is put into a non-empty cell,

E[X]=m−n+∑j=1n 1−pjm

Step by step solution

01

Step 1:Concept Introduction

Given that

Xi=1if a collision occurs when the item is placed

=0otherwise

X=Totalnumberofcollisions

=∑i=1m Xi

⇒E[X]=∑i=1m EXi

02

Step 2:Explanation

Molding on the cell in which it is set.

EXi=∑j EXi∣placed in celljpj

=∑j E[icauses collision∣Placed in cellj]pj

localid="1647435990293" =∑j 1−1−pji−1pj

localid="1647436010058" =1−∑j 1−pji−1pj

03

Step 3:Final Answer

The close to last uniformity utilized that, restrictive on the itemibeing set in the cellj, itemi will cause a collision if any of the previous(i-1) items were placed in a cellj, Thus,

E[X]=m−∑i=1m ∑j=1n 1−pji−1pj

Exchanging the request for the summation gives

E[X]=m−n+∑j=1n 1−pjm

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