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Prove thatE[g(X)YX]=g(X)E[YX].

Short Answer

Expert verified

We prove that,E[g(X)YX]=g(X)E[YX]

Step by step solution

01

Given information

Given in the question that, we have to prove thatE[g(X)YX]=g(X)E[YX]

02

Explanation

Because of the clarity, suppose that Xand Yare continuous random variables with its density functions. Take any xsuppfX. We have that

E(g(X)YX=x)=2g(x)yf(X,Y)X=x(x,y)dxdy

But, we have that

f(X,Y)X=x(x,y)dxdy=fYX(yx)dy

So the integral becomes

g(x)yfYX(yx)dy

Which is equal to

g(X)E(YX=x)

Since the relation hold for every xsuppf, we end up with

E(g(X)YX)=g(X)E(YX)

03

Final answer

We prove that,E[g(X)YX]=g(X)E[YX]

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