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91Ó°ÊÓ

Prove Proposition 2.1when

(a)Xand Yhave a joint probability mass function;

(b)Xand Yhave a joint probability density function and

g(x,y)≥0for all x,y.

Short Answer

Expert verified

(a). A joint probability mass function is proved as ∑z∈g(A,B)zP(g(X,Y)=z)=∑x,yg(x,y)p(x,y).

(b). A joint probability density function is proved as∫0∞∬g(x,y)>tf(x,y)dxdydt=∬x,y∫0g(x,y)f(x,y)dtdxdy=∬x,yg(x,y)f(x,y)dxdy.

Step by step solution

01

Given Information part(a)

A joint probability function.

02

Explanation part(a) 

Hence, the random variable assumes is,

The mean is

E(g(X,Y))=∑z∈g(A,B)zP(g(X,Y)=z)

Now, observe that every z∈g(A,B)has form z=g(x,y)for some xinAand yinB.

03

Explanation part(a) 

Also we have that,

P(g(X,Y)=z)=P(g(X,Y)=g(x,y))=P((X,Y)=(x,y))=p(x,y)

So we finally we have that,

∑z∈g(A,B)zP(g(X,Y)=z)=∑x,yg(x,y)p(x,y)

Therefore, we have proved the claimed.

04

Final answer part(a) 

A joint probability mass function is proved as∑z∈g(A,B)zP(g(X,Y)=z)=∑x,yg(x,y)p(x,y).

05

Given Information part(b)

A joint probability density function

06

Explanation part(b) 

Using the fact that the expectation of random variable can be written as an integral where we integrate , we have that

Also we have that,

07

Explanation part(b) 

which yields that

Changing the order of integration, we have that

so we have proved the claimed.

08

Final answer part(b)

A joint probability density function is proved as .

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Most popular questions from this chapter

The game of Clue involves 6 suspects, 6 weapons, and 9 rooms. One of each is randomly chosen and the object of the game is to guess the chosen three.

(a) How many solutions are possible? In one version of the game, the selection is made and then each of the players is randomly given three of the remaining cards. Let S, W, and R be, respectively, the numbers of suspects, weapons, and rooms in the set of three cards given to a specified player. Also, let X denote the number of solutions that are possible after that player observes his or her three cards.

(b) Express X in terms of S, W, and R.

(c) Find E[X]

The joint density of X and Yis given by f(x,y)=e-x/ye-yy,0<x<∞,0<y<∞, Compute EX2∣Y=y.

A coin having probability p of coming up heads is continually flipped until both heads and tails have appeared. Find

(a) the expected number of flips,

(b) the probability that the last flip lands on heads.

LetU1,U2,...be a sequence of independent uniform(0,1)random variables. In Example 5i, we showed that for 0≤x≤1,E[N(x)]=ex, where

N(x)=minn:∑i=1n Ui>x

This problem gives another approach to establishing that result.

(a) Show by induction on n that for 0<x≤10 and all n≥0

P{N(x)≥n+1}=xnn!

Hint: First condition onU1and then use the induction hypothesis.

use part (a) to conclude that

E[N(x)]=ex

There are n items in a box labeled H and m in a box labeled T. A coin that comes up heads with probability p and tails with probability 1 − p is flipped. Each time it comes up heads, an item is removed from the H box, and each time it comes up tails, an item is removed from the T box. (If a box is empty and its outcome occurs, then no items are removed.) Find the expected number of coin flips needed for both boxes to become empty. Hint: Condition on the number of heads in the first n + m flips.

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