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Show that ifE[X]<0androle="math" localid="1649871241073" 0is such thatEeX=1, then>0.

Short Answer

Expert verified

Consider the functionf(y)=-ln(y),y>0. Since this function is convex, if we letY=eX, using Jensen's inequalityE[f(Y)]f(E[Y]),

Step by step solution

01

Given Information.

E[X]<0and 0is such thatEeX=1, then>0.

02

Explanation.

Assume thatE[X]<0and 0such thatEeX=1, whereby is a scalar. We want to show that>0. To do this, we will use Jensen's inequality. It says that for a convex function fand an arbitrary random variable Yis

E[f(Y)]f(E[Y])

Consider the functionf(y)=-ln(y),y>0. Since this function is convex, if we letY=eX, using Jensen's inequality, we get:

E-lneX-lnEeX

Sincelneu=u, for eachu, and using the informationEeX=1, we get:

E[-X]-ln(1)=0

if properties of expectation

-E[X]0

it is givenE[X]<0

-<0

-<0

>0.

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