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For some constant c, the random variable X has the probability density function:

f(x)=cx4鈥呪赌呪赌呪赌0<x<20鈥呪赌呪赌呪赌otherwise

Find

  1. E[X]and
  2. Var(X)

Short Answer

Expert verified

a. The value of E[X]=53

b. Var(X)=563

Step by step solution

01

Step:1 Given Information (Part a)

The random variable X has the probability density function

f(x)=cx4鈥呪赌呪赌呪赌0<x<20鈥呪赌呪赌呪赌otherwise

We have to findE[X]

02

Definition (part a)

The Probability Density Function (PDF) is a probability function that represents the density of a continuous random variable that falls inside a given range of values.

03

Step:3 Explanation (Part a)

Let's start by determining the c constant. There must be one,

1=f(x)dx=02cx4dx=cx5502=c325

which implies that c=532

(a) The mean value is

E(X)=xf(x)dx=02x532x4dx=53202x5dx=532x6602=532646=53

04

Explanation (Part b)

According to the information, We observe that:

EX2=02x25x432dx=532x7702

532270=5327128=207

Therefore Var(X):

localid="1650014593098" Var(X)=Ex2(E(x))2

localid="1649597273687" Var(X)=207532=563

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