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If Xis a normal random variable with parameters μ=10and σ2=36, compute

(a)role="math" localid="1646719347104" PX>5

(b)role="math" localid="1646719357568" P4<X<16

(c)role="math" localid="1646719367217" PX<8

(d)PX<20

(e)PX>16

Short Answer

Expert verified

The required answers are:

(a)PX>5=0.7977

(b)P4<X<16=0.6826

(c)role="math" localid="1646720604668" Px<8=0.3695

(d)PX<20=0.9522

(e)PX>16=0.1587

Step by step solution

01

Part (a) Step 1. Given information.

Here, it is given that:

μ=10σ2=36∴σ=36=6

02

Part (a) Step 2. Compute P(X>5).

P(X>5)=PX-μσ>5-106=Pz>5-106=1-Pz≤5-106=1-Pz≤0.8333=1-0.2023∴P(X>5)=0.7977

03

Part (b) Step 1. Compute P4<X<16.

P(4<X<16)=P4-106<X-μσ<16-106=P-1<z<1=P(z<1)-P(z<-1)=0.8413-0.1587∴P(4<X<16)=0.6826

04

Part (c) Step 1. Compute P(X<8).

P(X<8)=PX-μσ<8-106=Pz<-0.3333∴P(X<8)=0.3695

05

Part (d) Step 1. Compute PX<20.

P(X<20)=PX-μσ<20-106=Pz<1.6667∴P(X<20)=0.9522

06

Part (e) Step 1. Compute PX>16.

P(X>16)=PX-μσ>16-106=Pz>1=1-Pz≤1=1-0.8413∴P(X>16)=0.1587

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