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If Xis an exponential random variable with a mean1/, show that

EXk=k!kk=1,2,

Hint: Make use of the gamma density function to evaluate the preceding.

Short Answer

Expert verified

Using the equation of expectation, determine EXkand the Gamma function within the integral.

Step by step solution

01

Find the Exponential variable.

We are provided thatXis an exponential random variable with a mean 1In other words, we have got that X~Expo()By the idea about the mean of a function of a random variable quantity, we have that

localid="1649619285130" EXk=xkfX(x)dx=0xke-xdx

02

Calculate the integral.

Let's calculate the integral, we've that

0xke-xdx=0xke-xdx

Making substitutions s=xwe've that

localid="1649619305189" 0xke-xdx=0ske-sds=1k0ske-sds=(k+1)k

Finally, we've obtained that

localid="1649619316547" EXk=(k+1)k=k!k

Which has been claimed.

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